52,200m/min bro. Hope this is the right answer
Some commonly used techniques might be distillation and magnetism.
Distillation is basically a method of separating liquid mixture by basically boiling and condensing the different liquids. Since liquids don't have the same boiling points. one will evaporate first, and the other liquid or liquds will remaim.
Magnetism is a method of separating solid mixtures. One or some solids will get atracted to the magnet and the others will remain. Note that this only works if one of the solids has a magnetical property.
Hope it helped,
Happy homework/ study/ exam!
Answer:
4.99 mg of vitamin C are in the beaker.
Explanation:
Given that,
Weight of vitamin = 0.0499 g
Molar mass = 176.124 g/mol
Weight of water = 100.0 ml
We need to calculate the mg of vitamin C in the beaker
We dissolve 0.0499 g vitamin C in water to from 100.0 ml solution.
100 ml solution contain 49.9 mg vitamin C
Now, we take 10 ml of this vitamin C solution in breaker
Since, 100 ml solution =49.9 mg vitamin C
Therefore,
Hence, 4.99 mg of vitamin C are in the beaker.
Heat can be given to a substance without raising its temperature,When a substance is changing its physical state[for eg from solid to liquid and liquid to gas ]. The heat energy which has to be supplied to change the state of substance is called its Latent Heat. Latent heat does not raise the temperature .
Answer:
a) K_e = 0.1225 J, b) U = 1.96 J, c) v = 0.99 m / s
Explanation:
Let's use the simple harmonium movement expression
y = A cos (wt + Ф)
indicate that the amplitude is
A = 0.05 m
as the system is released, the velocity at the initial point is zero
v = dy / dt
v = - A w sin (wt + Ф)
for t = 0 s and v = 0 m/s
0 = - A w sin Ф
so Ф = 0
the expression of the movement is
y = 0.05 cos wt
The total energy of the system is
Em = ½ k A²
let's use conservation of energy
starting point. Spring if we stretch and we set the zero of our system at this point
Em₀ = K_e + U
Em₀ = 0
final point. When weight and elastic force are in balance
Em_f = K_e + U
Em_f = ½ k y² + m g (-y)
energy is conserved
Em₀ = Em_f
0 = ½ k y² + m g (-y)
k = 2mg / y
k = 2 4.00 9.8 / 0.050
k = 98 N / m
a) maximum elastic energy
K_e = ½ k A²
K_e = ½ 98 0.05²
K_e = 0.1225 J
b) the maximum gravitational energy
U = m g y
U = 4.00 9.8 0.05
U = 1.96 J
c) The maximum kinetic energy occurs when the spring is not stretched
U = K
mg h = ½ m v²
v = √2gh
v = √( 2 9.8 0.05)
v = 0.99 m / s
d) energy at any point
Em = K + U
