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FrozenT [24]
4 years ago
12

How many moles of sodium nitrate NaNO3 would be produced from the complete reaction of 253 g sodium chromate Na2CrO4

Chemistry
2 answers:
Elenna [48]4 years ago
7 0

Answer: 3.12

Hope you pass

Stolb23 [73]4 years ago
5 0
<h3><u>Answer;</u></h3>

= 3.12 moles of NaNO3

<h3><u>Explanation</u>;</h3>

The equation for the reaction is;

Pb(NO3)2+Na2CrO4 → PbCrO4+2NaNO3

Molar ratios in the reaction are ; 1 : 1 : 1 : 2

Which means; One mole of (Na2CrO4) produces two moles of (NaNO3)

We can calculate the number of moles of Na2CrO4,

Moles (na2CrO4) = 253g /162

                             = 1.56 moles

Moles of NaNO3 will be;

 = 1.56 moles x 2 = 3.12 moles

Therefore, the moles of NaNO3 that will be produced will be 3.12 moles

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Answer:

2

Step-by-step explanation:

A. Moles before mixing

<em>Beaker I: </em>

Moles of H⁺ = 0.100 L × 0.03 mol/1 L

                   = 3 × 10⁻³ mol

<em>Beaker II: </em>

Beaker II is basic, because [H⁺] < 10⁻⁷ mol·L⁻¹.

        H⁺][OH⁻] = 1 × 10⁻¹⁴   Divide each side by [H⁺]

             [OH⁻] = (1 × 10⁻¹⁴)/[H⁺]

             [OH⁻] = (1 × 10⁻¹⁴)/(1 × 10⁻¹²)

             [OH⁻] = 0.01 mol·L⁻¹

Moles of OH⁻ = 0.100 L × 0.01 mol/1 L

                      = 1 × 10⁻³ mol

B. Moles after mixing

                 H⁺    +    OH⁻   ⟶ H₂O

I/mol:      3 × 10⁻³   1 × 10⁻³

C/mol:   -1 × 10⁻³  -1 × 10⁻³

E/mol:    2 × 10⁻³          0

You have more moles of acid than base, so the base will be completely neutralized when you mix the solutions.

You will end up with 2 × 10⁻³ mol of H⁺ in 200 mL of solution.


C. pH

 [H⁺] = (2 × 10⁻³ mol)/(0.200 L)

        = 1 × 10⁻² mol·L⁻¹

 pH = -log[H⁺ ]

       = -log(1 × 10⁻²)

       = 2

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3 years ago
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Coefficient 2 should be placed in the equation before the nitric acid in the reactant so that the chemical reaction becomes balanced.

The given chemical reaction is,

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Here, the elements Hydrogen, Nitrogen, and Oxygen are unbalanced.

These elements are altogether found in HNO₃ on the reactant side and are found as nitrate and hydrogen gas on the product side.

To balance the equation, the coefficient 2 is to be added in the reactant side so that 2 moles of Hydrogen, Nitrogen, and Oxygen would be balanced with 2 moles of Nitrate and two moles of Nitrogen.

On adding 2 on reactant side, we get

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This gives us a balanced equation and thus the equation could be balanced this way.

Therefore, coefficient 2 is to be added to make the equation to be balanced.

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8 0
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Answer:

5m3

Explanation:

becuase density= mass/volume

rearrange to make = volume=mass/density

15/3= 5

3 0
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