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Tanya [424]
4 years ago
14

Which substance is a homogeneous mixture?

Chemistry
1 answer:
AlladinOne [14]4 years ago
8 0
An example of the substnce would be steel
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MATCH THE TERM WITH THE DEFINITION:
arlik [135]
Weathering definition= <span>wear away or change the appearance or texture of (something) by long exposure to the air.

Erosion definition= </span><span>the process of eroding or being eroded by wind, water, or other natural agents.

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these definitions are out of my textbook but in my own words.

4 0
3 years ago
Read 2 more answers
Consider the chemical reaction represented by the equation below:
svlad2 [7]

3 MgCl2 + 2 Al = 3 Mg + 2 AlCl3

Since we know that we have 12 moles of MgCl2 and enough Al, we don't need to figure out the exact amount of Al.

3 MgCl2 / 2 AlCl3  =  12 mol MgCl2 / x mol AlCl2

cross-multiply

3 MgCl2(x mol AlCl2)  =  12 mol MgCl2(2 AlCl3)

3x = 24

x=8

8 moles AlCl3

Alternatively, we know that we have 12 moles of MgCl2, and a coefficient of 3. This indicates a multiplier of 4 for the entire equation, meaning 2 AlCl3 multiplied by (4) = 8 moles

6 0
3 years ago
Less dense then gas
Slav-nsk [51]
Nothing is less dense than gas. gas is the least dense form of matter.
4 0
3 years ago
If you combine 230.0 mL of water at 25.00 ∘ C and 140.0 mL of water at 95.00 ∘ C, what is the final temperature of the mixture?
IgorLugansk [536]

<u>Answer:</u> The final temperature of the mixture is 51.49°C

<u>Explanation:</u>

When two samples of water are mixed, the heat released by the water at high temperature will be equal to the amount of heat absorbed by water at low temperature

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]       ......(1)

where,

q = heat absorbed or released

m_1 = mass of water at high temperature = 140 g     (Density of water = 1.00 g/mL)

m_2 = mass of water at low temperature = 230 g

T_{final} = final temperature = ?°C

T_1 = initial temperature of water at high temperature = 95.00°C

T_2 = initial temperature of water at low temperature = 25.00°C

c = specific heat of water= 4.186 J/g°C

Putting values in equation 1, we get:

140\times 4.186\times (T_{final}-95)=-[230\times 4.186\times (T_{final}-25)]

T_{final}=51.49^oC

Hence, the final temperature of the mixture is 51.49°C

5 0
4 years ago
A chemist writes a report to his superiors regarding his experiments to make a new compound. Which part of the scientific method
N76 [4]

I think the answer as communicating findings.

4 0
3 years ago
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