Copper II sulfate solution is blue.
Answer: Rate in terms of disappearance of
= ![-\frac{1d[NO]}{2dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1d%5BNO%5D%7D%7B2dt%7D)
Rate in terms of disappearance of
= ![-\frac{1d[Cl_2]}{1dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1d%5BCl_2%5D%7D%7B1dt%7D)
Rate in terms of appearance of
= ![\frac{1d[NOCl]}{2dt}](https://tex.z-dn.net/?f=%5Cfrac%7B1d%5BNOCl%5D%7D%7B2dt%7D)
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.
Rate in terms of disappearance of = ![-\frac{1d[NO]}{2dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1d%5BNO%5D%7D%7B2dt%7D)
Rate in terms of disappearance of = ![-\frac{1d[Cl_2]}{1dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1d%5BCl_2%5D%7D%7B1dt%7D)
Rate in terms of appearance of
= ![+\frac{1d[NOCl]}{2dt}](https://tex.z-dn.net/?f=%2B%5Cfrac%7B1d%5BNOCl%5D%7D%7B2dt%7D)
A compound accepts electrons from another substance to form a covalent bond. The compound acts as a Lewis base.
<h3>What are the most common acid-base theories?</h3>
- Arrhenius: acids release H⁺ and bases release OH⁻.
- Bronsted-Lowry: acids donate H⁺ and bases accept H⁺.
- Lewis: acids accept electrons and bases donate electrons.
A compound accepts electrons from another substance to form a covalent bond. Which term best describes this compound’s behavior?
- Lewis acid. YES.
- Arrhenius base. NO, because OH⁻ is not involved.
- Bronsted-Lowry acid. NO, because H⁺ is not involved.
- Bronsted-Lowry base. NO, because H⁺ is not involved.
A compound accepts electrons from another substance to form a covalent bond. The compound acts as a Lewis base.
Learn more about Lewis acid-base theory here: brainly.com/question/7031920
Answer:
E₁ ≅ 28.96 kJ/mol
Explanation:
Given that:
The activation energy of a certain uncatalyzed biochemical reaction is 50.0 kJ/mol,
Let the activation energy for a catalyzed biochemical reaction = E₁
E₁ = ??? (unknown)
Let the activation energy for an uncatalyzed biochemical reaction = E₂
E₂ = 50.0 kJ/mol
= 50,000 J/mol
Temperature (T) = 37°C
= (37+273.15)K
= 310.15K
Rate constant (R) = 8.314 J/mol/k
Also, let the constant rate for the catalyzed biochemical reaction = K₁
let the constant rate for the uncatalyzed biochemical reaction = K₂
If the rate constant for the reaction increases by a factor of 3.50 × 10³ as compared with the uncatalyzed reaction, That implies that:
K₁ = 3.50 × 10³
K₂ = 1
Now, to calculate the activation energy for the catalyzed reaction going by the following above parameter;
we can use the formula for Arrhenius equation;

If
&





E₁ ≅ 28.96 kJ/mol
∴ the activation energy for a catalyzed biochemical reaction (E₁) = 28.96 kJ/mol