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sergey [27]
4 years ago
11

A 1.2-m radius cylindrical region contains a uniform electric field along the cylinder axis. It is increasing uniformly with tim

e. To obtain a total displacement current of 2.0x10-­9 A through a cross section of the region, the magnitude of the electric field should change at a rate of:
Physics
1 answer:
eduard4 years ago
7 0

Answer:

The magnitude of rate of change of electric field is 49.95\ V/m{\cdot} s.

Explanation:

Given that,

Radius of the cylindrical region contains a uniform electric field along the cylinder axis, r = 1.2 m

Total displacement current through a cross section of the region, I=2\times 10^{-9}\ A

We need to find the rate of change of electric field. Its is given by the formula as follows :

\dfrac{dE}{dt}=\dfrac{I}{A\epsilon_o}\\\\\dfrac{dE}{dt}=\dfrac{2\times 10^{-9}}{\pi (1.2)^2\times 8.85\times 10^{-12}}\\\\\dfrac{dE}{dt}=49.95\ V/m{\cdot} s

So, the magnitude of rate of change of electric field is 49.95\ V/m{\cdot} s.

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<u>Answer</u>

46,200 J

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Andy is waiting at the signal. As soon as the light turns green, he accelerates his car at a uniform rate of 8.00 meters/second2
lbvjy [14]
-- The car starts from rest, and goes 8 m/s faster every second.

-- After 30 seconds, it's going (30 x 8) = 240 m/s.

-- Its average speed during that 30 sec is  (1/2) (0 + 240) = 120 m/s

-- Distance covered in 30 sec at an average speed of 120 m/s 

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___________________________________

The formula that has all of this in it is the formula for 
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       Distance = (1/2) · (acceleration) · (time)²

                       = (1/2) ·      (8 m/s²)     · (30 sec)²

                       =      (4 m/s²)          ·      (900 sec²)

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When you translate these numbers into units for which
we have an intuitive feeling, you find that this problem is 
quite bogus, but entertaining nonetheless.

When the light turns green, Andy mashes the pedal to the metal
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How does he do that ?

By accelerating at 8 m/s².  That's about 0.82 G  !

He does zero to 60 mph in 3.4 seconds, and at the end
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He doesn't need to worry about getting a speeding ticket.
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3 years ago
What graph would best represent acceleration as a function of mass when a constant force is applied?
Alex17521 [72]

The graphs of the acceleration as a function of mass and of the acceleration as a function of force are in attachment.

Explanation:

To answer both parts of the question, we refer to Newton's second law, which states that:

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a)

To answer this part, we re-arrange the previous equation as follows:

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Therefore, we notice that if a constant force is applied, the acceleration is inversely proportional to the mass of the object:

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this means that if the mass increases, the acceleration decreases, and if the mass decreases, the acceleration increases.

In a graph of acceleration vs mass, the curve representing this relationship would be a hyperbole. The graph is shown as the first graph in the attached picture.

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As before, we re-arrange the previous equation as follows:

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Here we notice that if the object has a constant mass, the acceleration is directly proportional to the force applied on the object:

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In a graph of acceleration vs force, the curve representing this relationship would be a straight line, as shown in the second graph in the attached picture.

Learn more about Newton's second law of motion here:

brainly.com/question/3820012

#LearnwithBrainly

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