Question

Can someone help pleaseeeeeee

Answer 1

Answer:

-5

Step-by-step explanation:

The parabolas equation is

(y - k)^2 = 4p(x - h)

Where h,k is the vertex

Substituting the vertex ad (2,-4)

(y - -4)^2 = 4p(x - 2)

(y +4)^2 = 4p(x - 2)

We need to find p from the other point they give us (-3,-3)

(-3 +4)^2 = 4p(-3 - 2)

1^2 = 4p (-5)

1 = -20p

Divide by -20

1/-20 = -20p/-20

-1/20 = p

Substituting back into the equation

(y +4)^2 = 4(-1/20)(x - 2)

Simplifying

(y +4)^2 = (-1/5)(x - 2)

FOILing

y^2 +8y +16 = -1/5x +2/5

Multiply by 5

5y^2 +40y +80 = -x +2

Subtract 2

5y^2 +40y +80-2 = -x +2-2

5y^2 +40y +78 = -x

Multiply by -1

-5y^2 -40y -78 = x

The coefficient of y^2  is -5