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Lapatulllka [165]
3 years ago
14

What is the buoyant force on an object that weighs 340 N and is floating on a lake? if you could explain the answer that would b

e nice.
Physics
1 answer:
Kryger [21]3 years ago
5 0

You just said that the object is "floating".  

(As soon as you said that, a picture of a duck flashed through my mind.  But then I knew right away that the duck could not be an accurate representation of the situation you're describing.  340 N would be <u><em>some duck</em></u> ... about 76 pounds ... and that duck would have been caught and eaten a long time ago. I mean ... what could a 76-pound duck do ?  Could it fly away ?  Could it run away ? ?  Not likely.)

So it's not a duck, but whatever it is, it's just sitting there on the water, floating.  What's important is that it's <u><em>not accelerating</em></u> up or down.  THAT tells us that the vertical forces on it are balanced so that there's NO NET vertical force on it at all.

What are the vertical forces on it ?  There's gravity, pulling it DOWN with a force of 340 N, and there's buoyancy, pushing it UP.  The SUM of those two forces must be <em>zero</em> ... otherwise the object would be accelerating up or down.

It's not.  So (gravity) + (buoyancy) must add up to zero.

The buoyant force on the object is <em>340 N UPward.</em>

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A & D

Explanation:

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From the options, only options A & D fits this definition of single-displacement reactions.

For option D: Both left and hand and right hand sides each have one element and one compound. We can see that K is substituted from KBr to join Cl to form KCl and Br2 on the right hand side.

For option A: Both left and hand and right hand sides each have one element and one compound. We can see that OH is substituted from 2H2O to join Mg to form Mg(OH)2 and H2 on the right hand side.

The other options are not correct because they don't involve only and element and a compound on each side of the reaction.

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