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Lapatulllka [165]
4 years ago
14

What is the buoyant force on an object that weighs 340 N and is floating on a lake? if you could explain the answer that would b

e nice.
Physics
1 answer:
Kryger [21]4 years ago
5 0

You just said that the object is "floating".  

(As soon as you said that, a picture of a duck flashed through my mind.  But then I knew right away that the duck could not be an accurate representation of the situation you're describing.  340 N would be <u><em>some duck</em></u> ... about 76 pounds ... and that duck would have been caught and eaten a long time ago. I mean ... what could a 76-pound duck do ?  Could it fly away ?  Could it run away ? ?  Not likely.)

So it's not a duck, but whatever it is, it's just sitting there on the water, floating.  What's important is that it's <u><em>not accelerating</em></u> up or down.  THAT tells us that the vertical forces on it are balanced so that there's NO NET vertical force on it at all.

What are the vertical forces on it ?  There's gravity, pulling it DOWN with a force of 340 N, and there's buoyancy, pushing it UP.  The SUM of those two forces must be <em>zero</em> ... otherwise the object would be accelerating up or down.

It's not.  So (gravity) + (buoyancy) must add up to zero.

The buoyant force on the object is <em>340 N UPward.</em>

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Answer:

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The length of a simple pendulum is 0.66 m, the pendulum bob has a mass of 310 grams, and it is released at an angle of 12 degree
lina2011 [118]
A) the periodic time is given by the equation;
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For the frequency will be obtained by 1/T (Hz)
T = 2 × 3.14 √ (0.66/9.81)
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Frequency = 1/T = f = 1/1.6289
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b)  The vertical distance, the height is given by
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Vertical fall at the lowest point = 0.66 - 0.65 = 0.01 m
Applying conservation of energy
energy lost (MgΔh) = KE gained (1/2mv²)
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c) total energy = KE + GPE = KE when GPE is equal to zero (at the lowest point possible)
Thus total energy is equal to;
E = 1/2mv²
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   = 0.0304 J


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