Answer:
Explanation:
Given that,
Radius of solenoid R = 4cm = 0.04m
Turn per length is N/l = 800 turns/m
The rate at which current is increasing di/dt = 3 A/s
Induced electric field?
At r = 2.2cm=0.022m
µo = 4π × 10^-7 Wb/A•m
The magnetic field inside a solenoid is give as
B = µo•N•I
The value of electric field (E) can
only be a function of the distance r from the solenoid’s axis and it give as,
From gauss law
∮E•dA =qenc/εo
We can find the tangential component of the electric field from Faraday’s law
∮E•dl = −dΦB/dt
We choose the path to be a circle of radius r centered on the cylinder axis. Because all the requested radii are inside the solenoid, the flux-area is the entire πr² area within the loop.
E∮dl = −d/dt •(πr²B)
2πrE = −πr²dB/dt
2πrE = −πr² d/dt(µo•N•I)
2πrE = −πr² × µo•N•dI/dt
Divide both sides by 2πr
E =- ½ r•µo•N•dI/dt
Now, substituting the given data
E = -½ × 0.022 × 4π ×10^-7 × 800 × 3
E = —3.32 × 10^-5 V/m
E = —33.2 µV/m
The magnitude of the electric field at a point 2.2 cm from the solenoid axis is 33.2 µV/m
where the negative sign denotes counter-clockwise electric field when looking along the direction of the solenoid’s magnetic field.
3.125 meters diving 10 and 3.2 the angel does not have a value in the equation but if you were to use it in a real life setting it will
Answer:
distance, x = 38.17 m
Given:
velocity of the football, v = 20.5 m/s
football projected at an angle, 
Period of flight, T = 2.15 s
Solution:
Since, the velocity is projected at some angle, so it can be resolved in horizontal and vertical components:
vertical component, 
horizontal component, 
the component responsible to cover certain distance is 
Therefore, the distance covered by the football, x is given by:
⇒ 
x = 38.17 m
<h2>
Initial velocity of the object = 31.4 m/s</h2>
Explanation:
If an object is thrown downward with an initial velocity of v₀, then the distance it travels is given by s = 4.9 t²+v₀t
Now an object is thrown downward from a cliff 400 m high and it travels 138.3 m in 3 sec. We need to find initial velocity of the object.
s = 4.9 t²+v₀t
138.3 = 4.9 x 3²+ v₀ x 3
3v₀ = 94.2
v₀ = 31.4 m/s
Initial velocity of the object = 31.4 m/s
