Answer: The possible molecular formula will be 
Explanation:
Mass of C= 27.3 g
Mass of O = 72.7 g
Step 1 : convert given masses into moles.
Moles of C =
Moles of O =
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =
For O =
The ratio of C : O = 1: 2
Hence the empirical formula is
The possible molecular formula will be=
That is correct…….. i think
Answer:
The answer to your question is AgCl
Explanation:
Data
Silver = Ag = 75%
Chlorine = Cl = 25%
1.- Convert percent numbers to grams
Silver = 75 g
Chlorine = 25 g
2.- Calculate the moles of each element
Mass number Ag = 108 g
Mass number Cl = 35.5 g
108 g of Ag ------------------ 1 mol
75 g of Ag ------------------ x
x = (75 x 1) / 108
x = 75 / 108
x = 0.69 moles
35.5 g of Cl ------------------ 1 mol
25 g of Cl ----------------- x
x = (25 x 1) / 35.5
x = 0.70 moles
3.- Divide by the lowest number of moles
Ag = 0.69/0.69 = 1
Cl = 0.70 / 0.69 = 1.02 ≈ 1
4.- Write the empirical formula
Ag₁ Cl₁ = AgCl
Hi,
The answer should be C.
Hope this helps, if you’d like further explanation please let me know.
Answer:
2.499 moles of sucrose
Explanation:
Divide by Avogadro's number