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kvv77 [185]
4 years ago
8

Within the visible spectrum, our experience of red is associated with ________. shorter wavelengths intermediate wavelengths wav

elengths of indeterminate length longer wavelengths
Physics
1 answer:
Jet001 [13]4 years ago
3 0
<span>Within the visible spectrum, our experience of red is associated with
the longest wavelengths visible to our eyes. 

Our experience of violet is associated with the shortest wavelengths
visible to our eyes.

And all the other colors are associated with the wavelengths that are
intermediate between those two extremes.</span>
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A string is vibrating between two posts as shown above. Students are to determine the speed of the wave within this string. They
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Answer:

The distance between two posts

Explanation:

As the students have already measured the amount of time necessary for the wave to oscillate up and down that is on the string between two posts,They have to measure the speed of the wave.

        ie  v=fλ

<em>They have to measure distance between the posts. </em>

Because wavelength is equal to the distance between the posts ie full length of string.

The frequency of the wave is calculated by

               f= 1/T

Where is the time period which the students have calculated ie the amount of time taken to oscillate up and down,

Thus the wave speed is calculated using formula

            v=λ/T

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A ball is thrown straight upward. How does the sign of the work done by gravity while the ball is traveling upward compare with
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A dense metal sphere is dropped from a 10-meter tower, and at the exact same time an identical metal sphere is thrown horizontal
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Answer:

A. Both spheres land at the same time.

Explanation:

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if two point charges are separated by 1.5 cm and have charge values of 2.0 and -4.0, respectively, what is the value of the mutu
RUDIKE [14]

Complete question:

if two point charges are separated by 1.5 cm and have charge values of +2.0 and -4.0 μC, respectively, what is the value of the mutual force between them.

Answer:

The mutual force between the two point charges is 319.64 N

Explanation:

Given;

distance between the two point charges, r = 1.5 cm = 1.5 x 10⁻² m

value of the charges, q₁ and q₂ = 2 μC and - μ4 C

Apply Coulomb's law;

F = \frac{k|q_1||q_2|}{r^2}

where;

F is the force of attraction between the two charges

|q₁| and |q₂| are the magnitude of the two charges

r is the distance between the two charges

k is Coulomb's constant = 8.99 x 10⁹ Nm²/C²

F = \frac{k|q_1||q_2|}{r^2} \\\\F = \frac{8.99*10^9 *4*10^{-6}*2*10^{-6}}{(1.5*10^{-2})^2} \\\\F = 319.64 \ N

Therefore, the mutual force between the two point charges is 319.64 N

4 0
3 years ago
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