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3 years ago

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1. A person walks 50 meters north, and then travels 150 meters to the south. What is the total distance they travelled? What is

their displacement from their starting position?
Please help ASAP

1 answer:

Illusion [34]3 years ago

8 0

Answer:

Total: 200 meters, Displacement: 100 meters South

Explanation:

First, add up the meters traveled to get the total distance.

50m + 150m = 200m

Lastly, displacement is the shortest distance from the initial position to the final position. The person first walked 50 meters north but then traveled 150 meters south. Therefore, their displacement was 100 meters south.

50m - 150m = -100m

(Note: Directions are vectors. North and East are positive vectors while South and West are negative)

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$y_{tot}=y_{max}+y_{down}$

$y_{tot} =\dfrac{2gH+v_0^2}{2g}+\dfrac{2gH+v_0^2}{2g}+H$

$\boxed{y_{tot} =\dfrac{2gH+v_0^2}{g}+H}$

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