You can mark, lift and clean a ball on the green, but it's a violation to do so when another ball is in motion, as your ball might influence the outcome of that stroke. You can also mark and clean your ball in some instances when it's off the green: cleaning it, for example, just to the point where you can identify it.
Answer
Any force greater 490N
Explanation
The force required just to make an object slide over a rough horizontal surface is any force greater that the static friction which given by;
![F=\mu_s mg.............(1)](https://tex.z-dn.net/?f=F%3D%5Cmu_s%20mg.............%281%29)
Given;
![\mu_s=0.5\\m=100kg\\g=9.8m/s^2](https://tex.z-dn.net/?f=%5Cmu_s%3D0.5%5C%5Cm%3D100kg%5C%5Cg%3D9.8m%2Fs%5E2)
Hence;
F = 0.5 x 100 x 9.8
F = 490N.
We will only need the coefficient of kinetic friction if we were asked to find the force required to keep the object moving uniformly. Usually, the force needed to keep an object moving uniformly over a rough surface is lesser that which is needed to start its motion.
In this problem, we were only asked to find the minimum force required to make the object move which we have done.
Newton's third law states that for every action, there is an equal and opposite reaction. When you let go of the ballon, you are letting the force out but the force also pushes the balloon back.
Answer:
vf=94.4 m/s
Explanation:
acceleration is the final velocity minus initial velocity divided by time
a = (vf-vi)/t
Given:
a= 14.2 m/s^2
vi= 0 (at rest)
t = 6.6
Solve for vf
a = (vf-vi)/t
a*t=vf-vi
(14.2)*(6.6)=vf - 0
vf=94.4 m/s
The car accelerates with magnitude <em>a</em> such that
31.3 m/s = 25.6 m/s + <em>a</em> (5.4 s)
→ <em>a</em> = (31.3 m/s - 25.6 m/s) / (5.4 s) ≈ 1.056 m/s²
Then the applied force has a magnitude <em>F</em> of
<em>F</em> = (1430 kg) <em>a</em> ≈ 1500 N