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Bas_tet [7]
1 year ago
10

A sound wave has a frequency of 250 Hz and a wavelength of 2.5 m. What is the speed of the wave?

Physics
1 answer:
Digiron [165]1 year ago
3 0

ANSWER

625 m/s

EXPLANATION

Given:

• The frequency of the sound wave, f = 250 Hz

,

• The wavelength, λ = 2.5 m

Find:

• The speed of the wave, v

The speed of a wave of wavelength λ and frequency f is given by,

v=f\cdot\lambda

Substitute the known values and solve,

v=250Hz\cdot2.5m=625m/s

Hence, the speed of the wave is 625 m/s.

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v = Δd / Δt

While acceleration is the rate of change in velocity over change in time, this is written as:

a = Δv / Δt

 

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8 0
3 years ago
Suppose (for this statement only), that q is moved from the origin but is still within both the surfaces. The flux through both
o-na [289]

Answer:

-True  - True  - true   - false -false - false

Explanation:

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7 0
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Using this formula Vj = V; + at, If a vehicle starts from rest
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t   = Elapsed time

The vehicle starts from rest (vo=0) and accelerates at a=4.5 m/s2 for t=8 seconds. The final speed is:

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5 0
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the average american receives 2.28 mSv dose equivalent from radon each year. Assuming you receive this dose, and it all comes fr
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Answer:

The approximate number of decays  this represent  is  N= 23*10^{10}  

Explanation:

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    The amount of Radiation received by an average american is I_a = 2.28 \ mSv

     The source of the radiation is S = 5.49 MeV \ alpha \ particle

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   Therefore  2.28 \ mSv = \frac{2.28}{1000} = 2.28 *10^{-3} J/kg

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  Therefore  2.28*10^{-3} \frac{J}{kg} = 2.28*10^{-3} \frac{J}{kg}  * \frac{1ev}{1.602*10^{-19} J} = 1.43*10^{16} ev/kg

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Cross-multiplying and making x the subject

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Where n is the approximate number of decay

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                                  N= 23*10^{10}  

                     

             

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Hope this helps!

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3 years ago
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