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storchak [24]
3 years ago
8

Using a dish-shaped mirror, a solar cooker concentrates the sun's energy onto a pot for cooking. A cooker with a 1.2-m-diameter

dish focuses the sun's energy onto a pot with a diameter of 25 cm What is the intensity at the base of the pot
Physics
1 answer:
Alekssandra [29.7K]3 years ago
3 0

Answer:

26500 W/m²

Explanation:

Given that:

The diameter of the dish d = 1.2 m

Assuming the Solar power P capture by the dish = 1300 W

The surface area of the pot is calculated by using the formula:

= \pi r^2

\pi \dfrac{d^2}{4}

where; the diameter = 25 cm

Area = \pi \dfrac{d^2}{4}

Area = \pi \dfrac{0.25^2}{4}

Area = 0.049 m²

The intensity is calculated by using the formula

I = power/area

I = 1300/0.049

I = 26530.6 W/m²

I ≅ 26500 W/m²

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