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stiv31 [10]
3 years ago
12

Which of the following best describes a vector?

Physics
1 answer:
garik1379 [7]3 years ago
5 0

Vectors are used to represent physical magnitudes that have an associated address. For example, if we want to represent the displacement of an object, it is not enough to describe only the distance as 10 meters, it is also necessary to describe in which direction the displacement occurred, for example, 30 ° towards the northeast.

Therefore the vectors are measured in one or several dimensions that include a magnitude and an address.

The correct option is the last:

"<em>a measurement in more than one dimension that includes a magnitude and a direction</em>"

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The orbital radii of four planets in our solar system are shown in the following table.
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Planet X would because it’s closer to the sun (radius is shorter).
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4 years ago
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A student leaving school travels 100 m East before he realizes he left his textbook in his locker. He heads back towards school,
andrew11 [14]

-- The overall <em>distance</em> he travels is (100m + 30m + 70m) = <em>200 meters</em>.

-- His <em>displacement </em>when he arrives at his front door is

D = (100m East) + (30m West) + (70m East)

D = (100m + 70m)East + (30m)West

D = (170m East) + (30m West)

<em>D = 140 meters East </em>

It's interesting to notice that his displacement is 60 meters shorter than the distance he walked.  

That's because there's a stretch of 30 meters somewhere in the middle that he actually covered <em>three times</em>.

Two of those times added to the distance his shoes covered (2x30m=60m), but they cancelled out of the displacement.

His front door is 140 meters East of school.  He walked 60m farther than that, going back and forth over the 30m piece.

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4 years ago
1.)Describe an experience where you encountered a buoyant force and tell what it felt like.
kap26 [50]

Swimming: Knowing I would not sink made feel safe.

Taking off in an aircraft: I felt heavier.

<u>Explanation:</u>

The buoyant force originates from the weight applied to the item by the liquid. Since the weight increments as the profundity press, the base of an article are constantly bigger than the power on the top - consequently the net upward power.

It follows up on an article inverse to gravity by liquid which is being submerged mostly or totally in the liquid. It contradicts the heaviness of the item. The buoyant force is given by volume dislodged by an item into the thickness of liquid into gravitational quickening.

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in which sample water do the water particle have more energy:5 grams of ice cubes at -10°c or 5 of a liquid water at 20°c?
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liquid water at 20 degrees Celsius

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An electric ceiling fan is rotating about a fixed axis with an initial angular velocity magnitude of 0.300 rev/s . The magnitude
Salsk061 [2.6K]

1) 1.2 m/s

First of all, we need to find the angular velocity of the blade at time t = 0.200 s. This is given by

\omega_f = \omega_i + \alpha t

where

\omega_i = 0.300 rev/s is the initial angular velocity

\alpha = 0.895 rev/s^2 is the angular acceleration

Substituting t = 0.200 s, we find

\omega_f = 0.300 + (0.895)(0.200)=0.479 rev/s

Let's now convert it into rad/s:

\omega_f = 2\pi \cdot 0.479 rev/s=3.01 rad/s

The distance of a point on the tip of the blade is equal to the radius of the blade, so half the diameter:

r=\frac{0.800}{2}=0.400 m

And so now we can find the tangential speed at t = 0.200 s:

v=\omega_f r =(3.01)(0.400)=1.2 m/s

2) 2.25 m/s^2

The tangential acceleration of a point rotating at a distance r from the centre of the circle is

a_t = \alpha r

where \alpha is the angular acceleration.

First of all, we need to convert the angular acceleration into rad/s^2:

\alpha = 0.895 rev/s^ \cdot 2 \pi =5.62 rad/s^2

A point on the tip of the blade has a distance of

r = 0.400 m

From the centre; so, the tangential acceleration is

a_t = (5.62)(0.400)=2.25 m/s^2

3) 3.6 m/s^2

The centripetal acceleration is given by

a=\frac{v^2}{r}

where

v is the tangential speed

r is the distance from the centre of the circle

We already calculate the tangential speed at point a):

v = 1.2 m/s

while the distance of a point at the end of the blade from the centre is

r = 0.400 m

Therefore, the centripetal acceleration is

a=\frac{1.2^2}{0.400}=3.6 m/s^2

7 0
3 years ago
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