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Makovka662 [10]
3 years ago
12

Annie has collected several items from around her house. She is using these objects to investigate which objects are attracted t

o magnets and which ones are not. Which item should Annie expect to be attracted to her magnet?
A) ice cube

B) metal screw

C) leather glove

D) notebook paper
Engineering
1 answer:
Margarita [4]3 years ago
5 0
The metal screw would be attracted to her magnet since its metal and the others don’t attract to magnets.
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The distribution of actual weights of 8‑ounce wedges of cheddar cheese produced at a dairy is Normal, with mean 8.1 ounces and s
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Answer:

sampling distribution

Explanation:

Sampling distribution is distribution of multiple samples' satistics of a population.

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A particle moving on a straight line has acceleration a = 5-3t, and its velocity is 7 at time t = 2. If s(t) is the distance fro
Vikki [24]

Given acceleration a = 5-3t, and its velocity is 7 at time t = 2, the value of s2 - s1 = 7

<h3>How to solve for the value of s2 - s1</h3>

We have

= \frac{dv}{dt} =v't = 5-3t\\\\\int\limits^a_b {v'(t)} \, dt

= \int\limits^a_b {(5-3t)} \, dt

5t - \frac{3t^2}{2} +c

v2 = 5x2 -  3x2 + c

= 10-6+c

= 4+c

s(t) = \frac{5t^2}{2} -\frac{t^3}{2} +3t + c

S2 - S1

=(5*\frac{4}{2} -\frac{8}{2} +3*2*c)-(\frac{5}{2} *1^2-\frac{1^2}{2} +3*1*c)

= 6 + 6+c - 2+3+c

12+c-5+c = 0

7 = c

Read more on acceleration here: brainly.com/question/605631

5 0
2 years ago
I ran across this symbol in some Electrical wiring documents and I am unaware of what this means. Any help?
Minchanka [31]

Answer:

Opened Push-button Switch (i.e. a PTM Switch)

Explanation:

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Since it's not touching and completing the line, the state of the switch is initially open.

6 0
3 years ago
Who developed the process of blueprinting?
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3 0
3 years ago
A 3-phase , 1MVA, 13.8kV/4160V, 60 Hz, transformer with Y-Delta winding connection is supplying a3-phase, 0.75 p.u. load on the
Tanya [424]

Answer:

a) 23.89 < -25.84 Ω

b) 31.38 < 25.84 A

c) 0.9323 leading

Explanation:

A) Calculate the load Impedance

current on load side = 0.75 p.u

power factor angle = 25.84

I_{load} = 0.75 < 25.84°

attached below is the remaining part of the solution

<u>B) Find the input current on the primary side in real units </u>

load current in primary = 31.38 < 25.84 A

<u>C) find the input power factor </u>

power factor = 0.9323 leading

<em></em>

<em>attached below is the detailed solution </em>

8 0
3 years ago
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