Answer:
The power transferred to the fluid is 1.8852 kW
Explanation:
Power = pressure drop × area × velocity
pressure drop = 20 kPa
area = πd^2/4 = 3.142×0.2^2/4 = 0.03142 m^2
velocity = 3 m/s
Power = 20 × 0.03142 × 3 = 1.8852 kJ/s = 1.8852 kW
When the handler has reached the point of balance of the animal, they should stop walking so that they may move only one animal at a time. The point of balance for cattle that are being worked with in limited places such as races and chutes is often found at the animal's shoulder, as seen by the diagrams.
This is further explained below.
<h3>What is a chute?</h3>
Generally, Chutes are channels, planes, or passageways that are either vertical or slanted and through which things may be transported using only gravity.
In conclusion, When the handler has reached the point where the animal's point of balance has been crossed, they should stop walking so that they may move just one animal.
As seen in the illustrations, the point of balance for cattle being worked with in restricted spaces like races and chutes is often located at the animal's shoulder.
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Answer:
Drawbacks include that it is costlier than other clean energies. Another thing is that when it isnt sunny you wont get as much energy
Answer:
Work = 651,1011 kJ
Explanation:
Let´s take the car as a system in order to apply the first law of thermodynamics as follows:

Where

And considering that there is no mass transfer and that the only energy flows that interact with the system are the heat losses and the work needed to move the car we have:

Regarding the energy system we have the following:

By doing the calculations we have:
![E_{system,final}- E_{system,initial}=[0,1*900]_{internal}+[0,5*900(30^2-10^2)/1000)_{kinetic}+(900*10*(20-0)/1000)_{potential}\\E_{system,final}- E_{system,initial}=90+360+180=630kJ](https://tex.z-dn.net/?f=E_%7Bsystem%2Cfinal%7D-%20E_%7Bsystem%2Cinitial%7D%3D%5B0%2C1%2A900%5D_%7Binternal%7D%2B%5B0%2C5%2A900%2830%5E2-10%5E2%29%2F1000%29_%7Bkinetic%7D%2B%28900%2A10%2A%2820-0%29%2F1000%29_%7Bpotential%7D%5C%5CE_%7Bsystem%2Cfinal%7D-%20E_%7Bsystem%2Cinitial%7D%3D90%2B360%2B180%3D630kJ)
Consider that in the previous calculation, the kinetic and potential energy terms were divided by 1.000 to change the units from J to kJ.
Finally, the work needed to move the car under the required conditions is calculated as follows:

Consider that in the previous calculation, the heat loss was changed previously from BTU to kJ.