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3 years ago

Calculate the pH of a 3.58x10^-9 M Nitric acid (a strong acid) solution

Chemistry

1 answer:

lubasha [3.4K]3 years ago

7 0

Answer:

pH= 8.45

Explanation:

when working with strong accids pH = -log(Concentration)

so -log(3.58e-9) = 8.446

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The oil would sink, due to the density of it

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4 years ago

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A student mixes in a test tube 3.00mL of 0.050M CuSO4with 7.00mL of 0.20M NH3/NH41 . The solution becomes a deep blue color. Ass

valkas [14]

Answer:

$\large \boxed{\text{0.0035 mol/L}}$

Explanation:

We are given the volumes and concentrations of two reactants, so this is a limiting reactant problem.

We know that we will need moles, so, lets assemble all the data in one place.

Cu²⁺ + 4NH₃ ⟶ Cu(NH₃)₄²⁺

V/mL: 3.00 7.00

c/mol·L⁻¹: 0.050 0.20

1. Identify the limiting reactant

(a) Calculate the moles of each reactant

$\text{Moles of Cu}^{2+}= \text{3.00 mL solution} \times \dfrac{\text{0.050 mmol Cu}^{2+}}{\text{1 mL solution}} = \text{0.150 mmol Cu}^{2+}\\\\\text{Moles of NH}_{3} = \text{7.00 mL solution} \times \dfrac{\text{0.20 mmol NH}_{3}}{\text{1 mL solution}} = \text{0.140 mmol NH}_{3}$

(b) Calculate the moles of Cu(NH₃)₄²⁺ that can be formed from each reactant

(i) From Cu²⁺

$\text{Moles of Cu(NH$_{3}$)$_{4}$$^{2+}$} = \text{0.150 mmol Cu}^{2+} \times \dfrac{\text{1 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}}{\text{1 mmol Cu}^{2+}}\\\\= \text{0.150 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}$

(ii) From NH₃

$\text{Moles of Cu(NH$_{3}$)$_{4}$$^{2+}$} = \text{0.140 mmol NH}_{3} \times \dfrac{\text{1 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}}{\text{4 mmol NH}_{3}}\\\\= \text{0.0350 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}$

NH₃ is the limiting reactant, because it forms fewer moles of the complex ion.

(c) Concentration of the complex ion

$\text{The reaction forms 0.0350 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$ in a total volume of 10.00 mL.}\\c = \dfrac{\text{moles}}{\text{litres}} = \dfrac{\text{0.0350 mmol}}{\text{10.00 mL}} = \textbf{0.0035 mol/L}\\\\\text{The concentration of the complex ion is $\large \boxed{\textbf{0.0035 mol/L}}$}$

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3 years ago

How many protons, electrons, and neutrons does an atom with an atomic

Mkey [24]

Answer:

Protons: 50

Neutrons: 70

Electrons: 50

Explanation:

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3 years ago

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A student makes several measurements of the density of an unknown mineral sample. She then reports the average value of these me

Tomtit [17]

Answer:

B). Precision.

Explanation:

During the course of measurements, two important factors are been seen to play key part which are accuracy and also precision. Precision here can reflect to the closeness of an answer towards the main value even though accuracy can show that too. Also it can show series of values been reproduced in the measurement flow; though in some cases can be a bit far from the actual value. Also its values are swen to be different because of repeatition and alsio in some cases, observational errors too.

4 0

3 years ago

For which δg°rxn = –30.5 kj/mol at 37.0 °c and ph 7.0. calculate the value of δgrxn in a biological cell in which [atp] = 5.0 mm

mario62 [17]

We are given ΔG°rxn = -30.5 kJ/mol for the following reaction:

ATP + H₂O → ADP + HPO₄²⁻

We are given a series of concentrations for each of the species and are asked to find the value of ΔG for the reaction. We can use the following formula:

ΔGrxn = ΔG°rxn + RTlnQ

We can use R = 0.008314 kJ/molK; T = 335.15 K and Q is the reaction quotient which can be found as follows, and be sure to first convert each concentration of mM to M:

Q = [ADP][HPO₄²⁻]/[ATP]
Q= [0.00010][0.005]/[0.005]
Q = 0.0001

Now we can use the above formula to solve for ΔGrxn.

ΔGrxn = -30.5 kJ/mol + (0.008314)(310.15)ln(0.00010)
ΔGrxn = -54.3 kJ/mol

The value of ΔGrxn = -54.3 kJ/mol.

6 0

3 years ago