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maxonik [38]
3 years ago
14

Balance the chemichal equation: NH3+CuO➡️Cu+N2+H2O

Chemistry
1 answer:
Gala2k [10]3 years ago
4 0
2NH3+3CuO➡️3Cu+N2+3H2O
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Which of these is a chemical property?
ankoles [38]

Answer:

The second choice, or flammability.

Explanation:

The flammability of something is how easy it is for it to burn or ignite.

7 0
3 years ago
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2. What is one effect of convection currents in the mantle?
Rom4ik [11]

Answer:

D no. is the answer of your question

8 0
3 years ago
A substance decays so that the amount a of the substance left at time t is given by: a = a0 ∙ (0.8)t where a0 is the original am
Zolol [24]

The half-life of the substance is 3.106 years.

<h3>What is the formula for exponential decay?</h3>
  • The exponential decline, which is a rapid reduction over time, can be calculated with the use of the exponential decay formula.
  • The exponential decay formula is used to determine population decay, half-life, radioactivity decay, and other phenomena.
  • The general form is F(x) = a.

Here,

a = the initial amount of substance

1-r is the decay rate

x = time span

The equation is given in its correct form as follows:

a = a_{0}×(0.8)^{t}

As this is an exponential decay of a first order reaction, t is an exponent of 0.8.

Now let's figure out the half life. Since the amount left is half of the initial amount at time t, that is when:

a = 0.5 a0

<h3>Substituting this into the equation:</h3>

0.5a_{0} = a_{0}×(0.8)^{t}

0.5 = (0.8)^{t}

taking log on both sides

t log 0.8 = log 0.5

t = log 0.5/log 0.8

t = 3.106 years

The half-life of the substance is 3.106 years.

To learn more about exponential decay formula visit:

brainly.com/question/28172854

#SPJ4

4 0
1 year ago
27 g of Al will react with how much mass of O2 to produce Al2O3
snow_tiger [21]
24g 4Al+3O2=2Al2O3
27g x(g)
108 96
X=24g
5 0
4 years ago
Element Z has a mass of 430g. Scientists determined it to have a ½ life of 5 years. How many grams of element Z will remain afte
Afina-wow [57]

Answer:

hope this helped youu:)

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3 years ago
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