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Dennis_Churaev [7]
3 years ago
11

When a ball is rolling down a hill, what forces are acting on the ball? Why does it speed up?

Chemistry
2 answers:
Blizzard [7]3 years ago
7 0

Answer:

the gravity speed up because the friction didn't speed up

Margaret [11]3 years ago
3 0

Answer:gravity

Explanation:

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Each of the following organs had a role in excretion, EXCEPT for the _____?
eimsori [14]

Answer:

c. the heart

all the rest actually will excrete, the heart is in a closed system so contributes to excretory organs but doesn't actually do it barring an accident

Explanation:

8 0
3 years ago
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When 20.0 g of KI are dissolved in 50.0 mL of distilled water in a calorimeter, the temperature drops from 24.0 °C to 19.0 °C. C
Reil [10]
<h2>Answer:</h2>

<em>8.67kJ/mol</em>

<h2>Explanations</h2>

The formula for calculating the amount of heat absorbed by the water is given as:

\begin{gathered} q=mc\triangle t \\ q=50\times4.18\frac{J}{g^oC}\times(19-24) \\ q=50\times4.18\times(-5) \\ q=-1045Joules \\ q=-1.045kJ \end{gathered}

Determine the moles of KI

\begin{gathered} moles\text{ of KI}=\frac{mass\text{ of KI}}{molar\text{ mass of KI}} \\ moles\text{ of KI}=\frac{20g}{166g\text{/mol}} \\ moles\text{ of KI}=0.1205moles \end{gathered}

Since heat is lost, hence the enthalpy change of the solution will be negative that is:

\begin{gathered} \triangle H=-q \\ \triangle H=-(-1.045kJ) \\ \triangle H=1.045kJ \end{gathered}

Determine the enthalpy of solution in kJ•mol-1

\begin{gathered} \triangle H_{diss}=\frac{1.045kJ}{0.1205mole} \\ \triangle H_{diss}\approx8.67kJmol^{-1} \end{gathered}

Hence the enthalpy of solution in kJ•mol-1 for KI is 8.67kJ/mol

4 0
1 year ago
Scientists can change society by defending their work in the face of controversy true or false
VMariaS [17]

they're not speaking to you and your family a very happy and prosperous new year and I will be there at first I thought it would be a good time to come by and see you soon

7 0
3 years ago
Consider this equilibrium: HCO31- + H2PO41- HPO42- + H2CO3. What are the Brønsted-Lowry acids in this equilibrium?
horrorfan [7]
To me i think the answer is c!
4 0
3 years ago
Read 2 more answers
The rate constant for this second‑order reaction is 0.190 M − 1 ⋅ s − 1 0.190 M−1⋅s−1 at 300 ∘ C. 300 ∘C. A ⟶ products A⟶product
Mamont248 [21]

Answer:

9.1 seconds

Explanation:

Given that for a second order reaction

1/[A]t = kt + 1/[A]o

Where [A]t= concentration at time = t= 0.340M

[A]o= initial concentration = 0.820M

k= rate constant for the reaction=0.190m-1s-1

t= time taken for the reaction (the unknown)

Hence;

(0.340)^-1 = 0.190×t + (0.820)^-1

t= (0.340)^-1 - (0.820)^-1/0.190

t= 9.1 seconds

Hence the time taken for the concentration to decrease from 0.840M to 0.340M is 9.1 seconds.

5 0
3 years ago
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