(8.08x10^24 H atoms)(3 C atoms/8 H atoms)
=3.03x10^24 C atoms
3.03x10^24+8.08x10^24=1.111x10^25 atoms total
(1.111x10^25)/(6.02x10^23)=18.4551495 mol C3H8
18.4551495(44.01)=812.2111296g C3H8
Answer:
2H2 + O2 -----> 2H2O
Not sure about the second question though.
put some water out with less salt and then some more water out with more salt and look at the differences with the freezing.
Sodium(Na) is the limiting reagent.
<h3>What is Limiting reagent?</h3>
The reactant that is totally consumed during a reaction, or the limiting reagent, decides when the process comes to an end. The precise quantity of reactant required to react with another element may be estimated from the reaction stoichiometry.
How do you identify a limiting reagent?
The limiting reactant is the one that is consumed first and sets a limit on the quantity of product(s) that can be produced. Calculate how many moles of each reactant are present and contrast this ratio with the mole ratio of the reactants in the balanced chemical equation to get the limiting reactant.
Start by writing the balanced chemical equation that describes this reaction
Notice that the reaction consumes 2 moles of sodium metal for every 1 mole of chlorine gas that takes part in the reaction and produces 2 moles of sodium chloride.
now we can see that we have 3 moles of sodium and 3 moles of chlorine, according to question. so, we can say that sodium is the limiting reagent in the given situation.
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