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den301095 [7]
3 years ago
12

What volume in liters of 5.75×10−2 M KH2AsO4 contains 6.30 g KH2AsO4?

Chemistry
1 answer:
AnnZ [28]3 years ago
3 0

Answer : The volume of solution is, 0.609 L

Explanation : Given,

Mass of KH_2AsO_4 = 6.30 g

Molar mass of KH_2AsO_4 = 180 g/mole

Concentration = 5.75\times 10^{-2}M

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Mass of }KH_2AsO_4}{\text{Molar mass of }KH_2AsO_4\times \text{Volume of solution (in L)}}

Now put all the given values in this formula, we get:

5.75\times 10^{-2}M=\frac{6.30g}{180g/mole\times \text{Volume of solution (in L)}}

\text{Volume of solution (in L)}=0.609L

Therefore, the volume of solution is, 0.609 L

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