Y=mx+c
since m=3
y=3x+c
Replacing for x and y;
4=3(2)+c
4=6+c
.c=-2
y=3x-2
Answer:
42 (square root>) 10 + 51 (square root>) 5
Step-by-step explanation:
To answer this question we will use the following slope-point formula for the equation of a line:
![y-y_1=m(x-x_1)\text{.}](https://tex.z-dn.net/?f=y-y_1%3Dm%28x-x_1%29%5Ctext%7B.%7D)
Therefore, the equation of the line that has a slope of 1/3 and passes through the point (-3,3) is:
![y-3=\frac{1}{3}(x-(-3))\text{.}](https://tex.z-dn.net/?f=y-3%3D%5Cfrac%7B1%7D%7B3%7D%28x-%28-3%29%29%5Ctext%7B.%7D)
Simplifying the above equation we get:
![\begin{gathered} y-3=\frac{1}{3}(x+3), \\ y-3=\frac{1}{3}x+1. \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20y-3%3D%5Cfrac%7B1%7D%7B3%7D%28x%2B3%29%2C%20%5C%5C%20y-3%3D%5Cfrac%7B1%7D%7B3%7Dx%2B1.%20%5Cend%7Bgathered%7D)
Adding 3 to the above equation we get:
![\begin{gathered} y-3+3=\frac{1}{3}x+1+3, \\ y=\frac{1}{3}x+4. \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20y-3%2B3%3D%5Cfrac%7B1%7D%7B3%7Dx%2B1%2B3%2C%20%5C%5C%20y%3D%5Cfrac%7B1%7D%7B3%7Dx%2B4.%20%5Cend%7Bgathered%7D)
Answer:
Answer:
The average of the two boys' points is p=3 is 19.4 points~
Step-by-step explanation:
What you need to do is that you plug p=3 into the expression [(5.4p+5)+(8+3.2p)]/2 and you have:[(5.4*3+5)+(8+3.2*3)]/2= (21.2+ 17.6)/2= 38.8/2= 19.4