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Leokris [45]
4 years ago
14

Simplify -4x^3 x 2y^-2 x 5y^5 x x^-8

Mathematics
1 answer:
n200080 [17]4 years ago
8 0
-4x^3\cdot \:2y^{-2}\cdot \:5y^5x^{-8} 

=2\cdot \:4\cdot \:5\cdot \dfrac{1}{y^2}x^{-8}x^3y^5 

=2\cdot \:4\cdot \:5\cdot \dfrac{1}{x^8}\cdot \frac{1}{y^2}x^3y^5 

=-\dfrac{1\cdot \:1\cdot \:4x^3\cdot \:2\cdot \:5y^5}{y^2x^8} 

=-\dfrac{2\cdot \:4\cdot \:5x^3y^5}{x^8y^2} 

=-\dfrac{40x^3y^5}{x^8y^2} 

=\dfrac{40y^5}{x^5y^2} 

=-\dfrac{40y^3}{x^5} 
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