Answer:
<h2>780</h2>
Step-by-step explanation:
What is the sum of the series 5^n from n=1 to 4.
5^1 + 5^2 + 5^3+ 5^4 =
5 + 25 + 125 + 625 =780
Answer:
The nth term of an AP will be 27 -7n.
Step-by-step explanation:
First five terms of the Arthemetic Sequence is given to us , which is 26 , 19 , 12 , 5
Hence here Common Difference can be found by subtracting two consecutive terms . Here which is 19 - 26 = (-7) .
Here first term is 26 .
And the nth term of an AP is given by ,
★ T_n = a + ( n - 1) d
<u>Subst</u><u>ituting</u><u> respective</u><u> values</u><u> </u><u>,</u>
⇒ T_n = a + ( n - 1 )d
⇒ T_n = 26 + (n - 1)(-7)
⇒ T_n = 26 -7n+1
⇒ T_n = 27 - 7n
<h3>
<u>Hence </u><u>the</u><u> </u><u>nth</u><u> </u><u>term</u><u> of</u><u> an</u><u> </u><u>AP</u><u> </u><u>can</u><u> </u><u>be</u><u> </u><u>found </u><u>using </u><u>T_</u><u>n</u><u> </u><u>=</u><u> </u><u>2</u><u>7</u><u> </u><u>-</u><u> </u><u>7</u><u>n</u><u>. </u></h3>
3x3x3x5x5 is in nonstandard form. Please, use " ^ " to denote exponentiation:
3x^3x^3x^5x^5.
Noting that a^b*a^c = a^(b+c), rewrite 3x^3x^3x^5x^5 as 3x^(3+3+5+5) = 3x^16.
Hey there, just multiply 2.2 by 5, 2.2×5=11. Therefore, the lowest common multiple of 2.2 and 5 is 11.
