Answer:
-14
Step-by-step explanation:
subtract
7x-32=3
7x=3+32
7x=35
x=35/7
x=5
HOPE IT HELPS U!!
have a great day ahead ! :)
let's recall that a cube is just a rectangular prism with all equal sides, check picture below.
![\bf \textit{volume of a cube}\\\\ V=s^3~~ \begin{cases} s=&length~of\\ &a~side\\ \cline{1-2} V=&27000 \end{cases}\implies 27000=s^3\implies \sqrt[3]{27000}=s\implies 30=s \\\\[-0.35em] ~\dotfill\\\\ \textit{surface area of a cube}\\\\ SA=6s~~\begin{cases} s=&length~of\\ &a~side\\ \cline{1-2} s=&30 \end{cases}\implies SA=6(30)\implies SA=180](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cube%7D%5C%5C%5C%5C%20V%3Ds%5E3~~%20%5Cbegin%7Bcases%7D%20s%3D%26length~of%5C%5C%20%26a~side%5C%5C%20%5Ccline%7B1-2%7D%20V%3D%2627000%20%5Cend%7Bcases%7D%5Cimplies%2027000%3Ds%5E3%5Cimplies%20%5Csqrt%5B3%5D%7B27000%7D%3Ds%5Cimplies%2030%3Ds%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ctextit%7Bsurface%20area%20of%20a%20cube%7D%5C%5C%5C%5C%20SA%3D6s~~%5Cbegin%7Bcases%7D%20s%3D%26length~of%5C%5C%20%26a~side%5C%5C%20%5Ccline%7B1-2%7D%20s%3D%2630%20%5Cend%7Bcases%7D%5Cimplies%20SA%3D6%2830%29%5Cimplies%20SA%3D180)
Answer:
29.42 units
Step-by-step explanation:
<u>1) Find the perimeter around the semi-circle</u>
To do this, we find the circumference of the circle using the given diameter:
where d is the diameter
Plug in 6 as the diameter

Divide the circumference by 2

Therefore, the perimeter around the semi-circle is 3π units.
<u>2) Find the perimeter around the rest of the shape</u>
Although it's impossible to determine the lengths of the varied sides on the right side of the shape, we know that all of those <em>vertical</em> sides facing the right add up to 6. We also know that all of those <em>horizontal </em>sides facing up add up to 7. Please refer to the attached images.
Therefore, we add the following:
7+6+7
= 20
Therefore, the perimeter around that area of the shape is 20 units.
<u>3) Add the perimeter around the semi-circle and the perimeter around the rest of the shape</u>

Therefore, the perimeter of the shape is approximately 29.42 units.
I hope this helps!