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Amiraneli [1.4K]
3 years ago
11

Three forces act simultaneously on point j. one force is 10 newton's north

Physics
1 answer:
Mashcka [7]3 years ago
5 0

Answer:

The answer is 24.2 N.

Explanation:

Y- component = 10 N + 15 cos (30) = 23 N (North)

X - component = 15 N - 15 sin (30) = 7.5 N (west)

As, East, west and North are opposite direction so minus,

Magnitude = √ 23² + 7.5²

                  = 24.2 N.

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The human body has an average density of 979 kg/m3 , what fraction of a person is submerged when floating gently in fresh water?
FromTheMoon [43]

A person is submerged of about 97.9%.

The average density of the human body is given as 979 kg/ m³.

<h3>Define Law of floatation.</h3>

    Law of floatation can be defined as the volume of the liquid displaced when a body floats on the liquid surface is equal to the body submerged in the water.

As body has the stable equilibrium state, the buoyancy of the fluid will be equal to the weight.

Weight of the body floating = Weight of the body immersed in fluid

  Law of floatation = Density of the floating object / density of fluid

 As fluid is the freshwater here, the density of fluid will be 1000 kg/ m³.

                               = (979 kg/ m³) / ( 1000 kg/ m³)

                               = 97.9 %

A person is submerged when floating gently in fresh water about 97.9%.

Learn more about law of floatation,

brainly.com/question/17032479

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4 0
10 months ago
Two hockey pucks, labeled A and B, are initially at rest on a smooth ice surface and are separated by a distance of 18.0 m . Sim
Nonamiya [84]

Answer:

The distance covered by puck A before collision is  z = 8.56 \ m

Explanation:

From the question we are told that

   The label on the two hockey pucks is  A and  B

    The distance between the  two hockey pucks is D   18.0 m

     The speed of puck A is  v_A =  3.90 \ m/s

        The speed of puck B is  v_B  =  4.30 \ m/s

The distance covered by puck A is mathematically represented as

     z =  v_A * t

  =>  t  =  \frac{z}{v_A}

 The distance covered by puck B  is  mathematically represented as

      18 - z =  v_B  * t

=>   t  = \frac{18 - z}{v_B}

Since the time take before collision is the same

        \frac{18 - z}{V_B}  =  \frac{z}{v_A}

substituting values

          \frac{18 -z }{4.3}  = \frac{z}{3.90}

=>      70.2 - 3.90 z   = 4.3 z

=>       z = 8.56 \ m

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What would happen to a 100N gravitational force if both masses were doubled and the radius were
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Answer:

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Explanation:

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