All categories

3 years ago

Three forces act simultaneously on point j. one force is 10 newton's north

Physics

1 answer:

Mashcka [7]3 years ago

5 0

Answer:

The answer is 24.2 N.

Explanation:

Y- component = 10 N + 15 cos (30) = 23 N (North)

X - component = 15 N - 15 sin (30) = 7.5 N (west)

As, East, west and North are opposite direction so minus,

Magnitude = √ 23² + 7.5²

= 24.2 N.

You might be interested in

A transverse traveling wave on a cord is represented by, where D and x are in meters and t is in seconds.

yarga [219]

Answer with Explanation:

We are given that a transverse travelling wave on a cord is represented by

$D=0.51sin(6.1x+76t)$

Where D and x in meters

t(in seconds)

a.General equation of transverse wave

$y=Asin(kx+\omega t)$

By comparing we get

A=0.51

$k=6.1$

$k=\frac{2\pi}{\lambda}$

Wavelength, $\lambda=\frac{2\pi}{k}=\frac{2\pi}{6.1}=1.03$

b. $\omega=76$

Frequency, $f=\frac{\omega}{2\pi}=\frac{76}{2\pi}=12.096Hz$

c.Velocity, $v=f\lambda=12.096\times 1.03=12.46m/s$

Direction:Towards negative x- axis

d.Amplitude,A=0.51 m

e.Maximum speed, $v_{max}=A\omega=0.51\times 76=38.76 m/s$

Minimum speed, $v_{min}=0$

6 0

4 years ago

This is an image of a stream table modeling how water can change surface features of Earth. Which of the following processes is

DaniilM [7]

The answer would be deposition

3 0

3 years ago

You push downward on a trunk at an angle 25° below the horizontal with a force of If the trunk is on a flat surface and the coef

Sophie [7]

Complete question is;

You push downward on a trunk at an angle 25° below the horizontal with a force of 750N. if the trunk is on a flat surface and the coefficient of static friction between the surface and the trunk is 0.61, what is the most massive trunk you will be able to move?

Answer:

The most massive trunk is about 81.3 kg

Explanation:

I've attached a free body diagram that depicts this question.

Where;

N = normal force on the trunk

m = mass of the trunk

W = weight of the trunk = mg

F = static frictional force

Using equilibrium of force in vertical direction, we obtain;

N = W + 750 Sin25

N = mg + 750 Sin25 - - - - (eq 1)

Now, we are given that Coefficient of static friction: μ = 0.61

static frictional force is given by the formula;

F = μN

Since N = mg + 750 Sin25, we now have;

F = (0.61) (mg + 750 Sin25) - - - (eq 2)

Along the horizontal direction, for the trunk to move, force equation must be;

F = 750 Cos25

Thus, we now have;

750 Cos25 = 0.61(mg + 750 Sin25)

g = 9.81.

So,we now have ;

750 Cos25 = 0.61(m(9.81) + 750Sin25)

750 × 0.9063 = 0.61(9.81m + (750 × 0.4226))

Divide both sides by 0.61;

(750 × 0.9063)/0.61 = 9.81m + 316.95

1114.3 = 9.81m + 316.95

1114.3 - 316.95 = 9.81m

797.35 = 9.81m

m = 797.35/9.81

m = 81.3 kg

7 0

3 years ago

Every year, new records in track and field events are recorded. Let's take an historic look back at some exciting races.

Hitman42 [59]

First we need to turn Aouita's time for the race into seconds. There are 60 seconds in a minute, so 7 minutes and 29.45 seconds is (7 x 60) + 29.45 = 449.45. He ran 3000 meters in that time, so his average speed was 3000 meters divided by 449.45 seconds. 3000 / 449.45 = 6.67 m/s. So, on average, he covered 6.67 meters (more than 21 feet!) during each second of the race.

4 0

3 years ago

Why do people make this to the seashore?

Nadya [2.5K]

Answer:

Protecting the Seashore

Seashore Conservation Code

When investigating a seashore it is important to remember that the welfare of the plants and animals must come first. If seaweeds are attached to rocks do not try to pull them off, just examine them where they are growing. Handle animals with great care, returning them to the place where they were found. Anemones and limpets are normally firmly stuck to rocks and any attempt to remove them may result in their death. Replace any large stones that are removed – animals that live on the underside soon die if left exposed.

Pollution Problems

Seas and seashores are under continual threat from pollution. Here are some examples:-

oil rigOil spills, either accidental or deliberate, have a devastating effect on marine life, especially seabirds. Black tar-like oil washed up on a rocky shore would obviously completely destroy the entire community of living things. Chemicals used to disperse oil spills on a shore may effectively clean up the oil, but they can also cleanse the shore of life! The best policy for marine life is to physically remove as much oil as possible and leave the rest to degrade naturally. A rocky shore will recover much more quickly if chemicals are not used.

Sewage and litter also upsets seashore ecosystem, making them unsightly and perhaps contaminated. Some litter can be dangerous to wildlife.

Toxic chemicals and radioactive waste - a cocktail of toxic chemicals have found their way into the sea over the years, affecting both marine and human life. For many years potentially deadly radioactive waste from nuclear power stations and other sources was disposed of in the sea, and beaches have been contaminated by accidental leakages from nuclear power stations.

Explanation:

5 0

3 years ago

Read 2 more answers