Answer:
Option D is the correct answer.
Explanation:
We equation for elongation
Here we need to find weight required,
We need to stretch a steel road by 2 mm, that is ΔL = 2mm = 0.002 m
E = 200GPa = 2 x 10¹¹ N/m²
L=2m
Substituting
Option D is the correct answer.
Answer:
It requires more tension to pull up the track
Explanation:
Net force must be zero to maintain constant velocity.
Weight force will always be pointed down the slope. Call it W
Friction force (Call it Ff) will be down slope when movement is up slope.
Friction force will be up slope when movement is down slope.
W and Ff are always positive numbers
Call the pulling force T
If Up slope is considered the positive direction
Moving up slope
Tu - Ff - W = 0
Tu = Ff + W
Moving down slope
Td + W - Ff = 0
Td = Ff - W
Ff + W > Ff - W therefore Tu > Td
Answer:
<em>10.46m/s</em>
Explanation:
Given
Distance = 5.58m
Required
magnitude of the velocity'
Using the equation of motion expressed as
v² = u² + 2gS
v² = 0 +2(9.8)(5.58)
v² = 109.368
v= √109.368
v = 10.46m/s
<em>Hence the magnitude of the velocity of the of the chain is 10.46m/s</em>
Robert threw the Frisbee at 10 m/s.
This is because the formula for average speed is: v = d/t
v = Average speed or average velocity
d = Distance
t = Time
so the formula would say v = 50m/5s; v = 10m/s