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Amiraneli [1.4K]
3 years ago
11

Three forces act simultaneously on point j. one force is 10 newton's north

Physics
1 answer:
Mashcka [7]3 years ago
5 0

Answer:

The answer is 24.2 N.

Explanation:

Y- component = 10 N + 15 cos (30) = 23 N (North)

X - component = 15 N - 15 sin (30) = 7.5 N (west)

As, East, west and North are opposite direction so minus,

Magnitude = √ 23² + 7.5²

                  = 24.2 N.

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A ball is rolled at a velocity of 25 m/sec. after 13.5 seconds, it comes to a stop . What is the acceleration of the ball?
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Answer:

The answer to your question is a = -1.85 m/s² the acceleration is negative because it is coming to stop.

Explanation:

Data

vo = 25 m/s

t = 13.5 s

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Formula

vf = vo + at

solve for a

a = (vf - vo)/t

Substitution

a = (0 - 25) / 13.5

Simplification

a = -25/13.5

Result

a = -1.85 m/s²

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A 10.0-kg mass is placed on a 25.0o incline and friction keeps it from sliding. The coefficient of static friction in this case
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The frictional force while the mass is sliding will be 46.2 N.

<h3>What is friction force?</h3>

Opposition forces on the surface cause heat loss during the motion of an object known as the friction force.

Given data:

m(mass)= 10.0-kg

Θ (Inclination angle)=25.0o

Coefficient of sliding friction,\rm \mu_k=0.520

Coefficient of static friction,\rm  \mu_s=0.520

The friction force, F=?

Resolve the force in the inclined plane;

\rm F=\mu_s mg cos25^0 \\\\ F=0.520 \times 10 \times 9.81 \times  cos 25 ^0 \\\\ F= 46.2 \ N

Hence, the frictional force while the mass is sliding will be 46.2 N.

To know more about friction force refer to the link;

brainly.com/question/1714663

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