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melisa1 [442]
3 years ago
14

Planet Nine is speculated to be on average 20 times farther away from the Sun than Neptune (on average distance from the Sun). H

ow many miles from the Sun would this place Planet Nine on average? Divide 93 million miles into your result to get how many astronomical units (AU) Planet Nine would be on average away from the Sun.
Physics
1 answer:
saveliy_v [14]3 years ago
6 0

Answer:

The distance is 55.636 billion miles, or 528.2 AU.

Explanation:

Since the distance from the Sun to Neptune is 2.7818 billion miles, the distance from the Sun to Planet Nine would be 20 times that, which is:

d=(20)(2781800000\ miles)=55636000000\ miles

or 55.636 billion miles.

Since 1 astronomical unit (AU) is 93 million miles, that distance is also:

d=(55636000000\ miles)(\frac{1AU}{93000000\ miles})=598.2\ AU

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6. State whether each of the following is an example of conduction, convection, and/or radiation. Explain if you think there is
hodyreva [135]
A).  Convection is heating the soup in the pot.
When you stick the spoon into the hot soup,
conduction heats the spoon all the way up to the end.

b).  Water conducts heat a little bit. 
But convection is much more responsible for the
uniform distribution of temperature in the kiddie pool.

c).  The heat from the metal bench conducts directly
to the buttus epidermis when you sit on it.

d).  You feel the heat on your face ... but not on the back of your
neck ... on account of radiation from the fire and the hot grill.
3 0
3 years ago
Mercury has a radial acceleration of 3.96 × 10−2 m/s2 and its orbital period is T = 88 days. What is the radius of Mercury’s orb
Maslowich

Answer: 58,045,522,878.8 meters

Explanation:

Ok, the data we have is

Period = T = 88 days

Radial acceleration = ar = 3.96x10^-2 m/s^2

And we know that the equation for the radial acceleration is:

ar = v^2/r = r*w^2

Where v is the velocity. r is the radius and w is the angular velocity.

And we know that:

w = 2*pi*f

where f is the frequency, and:

T = 1/f.

Then we can write:

w = 2*pi/T

and our equation becomes:

ar = r*(2*pi/T)^2

Now we solve this for r.

First we need to use the same units in both equations, so we want to write T in seconds.

T = 88 days,

A day has 24 hours, and one hour has 3600 seconds:

T = 88*24*3600 s =7,603,200s

Then:

3.96x10^-2 m/s^2 = r*(2*3.14/7,603,200s)^2

r = (3.96x10^-2 m/s^2) /(2*3.14/7,603,200s)^2 = 58,045,522,878.8 meters

5 0
3 years ago
11. Which of the following is a proper unit of
Sergeeva-Olga [200]
D is the correct answer!!
4 0
2 years ago
Read 2 more answers
If both of these balls are traveling down a bowling lane at the SAME speed, which one would would have more kinetic energy?
Mariana [72]
<h2>Answer:</h2>

<u>Ball A has more kinetic energy</u>

<h2>Explanation:</h2>

As we know that Kinetic energy is given by

K. E = 1/2 mv²

Since K E is dependent upon both mass and velocity so increasing mass will produce more kinetic energy if the speed remains constant

As the mass of ball A is greater than ball B so we can say that the kinetic energy of ball is more than ball B


3 0
3 years ago
A boy standing on the bridge kicks a stone into the water below. He kicks the stone with a horizontal velocity of 8.06 m/s. It l
Ronch [10]

Time taken to reach water :

t = \dfrac{D}{v}\\\\t=\dfrac{6.78}{8.06}\ s\\\\t=0.84\ s

Now, initial vertical speed , u = 0 m/s.

By equation of motion :

h = ut +\dfrac{at^2}{2}

Here, a = g = acceleration due to gravity = 9.8 m/s².

So,

h = 0(t) +\dfrac{9.8\times 0.84^2}{2}\\\\h=3.46\ m

Therefore, the height of the bridge is 3.46 m.

Hence, this is the required solution.

6 0
3 years ago
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