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Verdich [7]
3 years ago
10

Captain Jessica has a ship, the H.M.S Crimson Lynx. The ship is two furlongs from the dread pirate Ishaan and his merciless band

of thieves. If her ship hasn't already been hit, Captain Jessica has probability \dfrac{2}{5} 5 2 ​ start fraction, 2, divided by, 5, end fraction of hitting the pirate ship. If her ship has been hit, Captain Jessica will always miss. If his ship hasn't already been hit, dread pirate Ishaan has probability \dfrac{3}{8} 8 3 ​ start fraction, 3, divided by, 8, end fraction of hitting the Captain's ship. If his ship has been hit, dread pirate Ishaan will always miss. If the Captain and the pirate each shoot once, and the Captain shoots first, what is the probability that the Captain misses the pirate ship, but the pirate hits?
Mathematics
1 answer:
OLga [1]3 years ago
6 0

Answer:

9/40

Step-by-step explanation:

Captain Jessica shoots first.  This means her ship has not already been hit, which means she has a 2/5 chance of hitting the pirate ship.  This also means she has a 1-2/5 = 3/5 chance of missing the pirate ship.

Since Captain Jessica misses, dread pirate Ishaan has a 3/8 chance of hitting the captain's ship.  This means he has a

3/5(3/8) = 9/40 chance of the captain missing the pirate and the pirate hitting the captain.

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Hi!

3x - 30 = x + 10

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3x - 30 + 30 = x + 10 + 30

3x = x + 40

<h3>Subtract x from both sides. </h3>

3x - x = x - x + 40

2x = 40

<h3>Divide by 2 on both sides</h3>

2x/2 = 40/2

<u>x = 20</u>

<h2>The answer is x = 20</h2>

Hope this helps! :)

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nalin [4]

Answer:

V= 14.13

Step-by-step explanation:

Information needed:

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Answer:

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Step-by-step explanation:

Since this is a ratio question and we only have variable that we need to solve (total people that entered last week), Then we can use the Rule of Three to solve this problem. We do this by multiplying the diagonal values of the following model and dividing by the third value in order to find the variable, like so...

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