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3 years ago

A boy is pushing forward on a crate with a force of 100 newtons. the reaction force is

1 answer:

4 0

According to Newtons 3rd law of Motion, for every action, there is an equal and opposite reaction. So if the boy is pushing forward on a crate with a force of 100 newtons, the crate is pushing back on the boy with a force of 100 newtons. Hope this helps

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In an economy, the demand for labor is given by the equation W = 15 - (1/200) L and the supply of labor is given by the equation

mr_godi [17]

Answer:

the equilibrium wage rate is 10 and the equilibrium quantity of labor is 1000 workers

Explanation:

The equilibrium wage rate and the equilibrium quantity of labor are found as the point where the equation of demand intercepts the equation of supply, so the equilibrium quantity of labor is:

$W_{Demand} = W_{Supply}$

15 - (1/200) L = 5 + (1/200) L

15 - 5 = (1/200) L + (1/200) L

10 = (2/200) L

(10*200)/2 = L

1000 = L

Then, the equilibrium wage rate is calculated using either the equation of demand for labor or the equation of supply of labor. If we use the equation of demand for labor, we get:

W = 15 - (1/200) L

W = 15 - (1/200) 1000

W = 10

Finally, the equilibrium wage rate is 10 and the equilibrium quantity of labor is 1000 workers

7 0

3 years ago

Katie, a 40 kg child, climbs a tree to rescue her cat who is afraid to jump 9.4 m to the ground. How much work does Katie do to

Diano4ka-milaya [45]

Answer:

The work done by the child to reach the cat is, W = 3684.8 J

Explanation:

Given data,

The mass of the child, m = 40 kg

The height of the cat from the ground, h = 9.4 m

The force acting on the child due to gravitational force is,

F = mg

The minimum force required by the child to climb the tree against the gravitational force is,

F = mg

Hence, the work done by the child is,

W = F · h

= 40 x 9.8 x 9.4

= 3684.8 joules

Hence, the work done by the child to reach the cat is, W = 3684.8 J

4 0

3 years ago

Is this circuit parallel??????

kobusy [5.1K]

Answer:

yes it is parrell

Explanation:

7 0

2 years ago

An unwary football player collides with a padded goalpost while running at a velocity of 5.70 m/s and comes to a full stop after

ollegr [7]

The relationship between the initial velocity, final velociy, distance, and deceleration can be expressed in the following equation.

2(a)(0.270 m) = 0² - (5.70 m/s)²

The value of a (which is the deceleration) is 0.06 m/s². Thus, the answer is that the deceleration value is approximately 0.06 m/s².

6 0

4 years ago

What is angular frequency

Firlakuza [10]

Measures angular displacement per unit time.

7 0

3 years ago

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