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Dennis_Churaev [7]
3 years ago
7

If force = mass x acceleration, What is the force applied to a 20 kg rock that is acceleration at a 20 m/s^2?

Physics
2 answers:
lys-0071 [83]3 years ago
5 0

Answer: 400 N

Explanation:

Newton's second law states that the force applied to an object is directly proportional to the acceleration of the object, following the relationship

F=ma

where

F is the force applied

m is the mass of the object

a is the acceleration

In this problem, we have

m=20 kg is the mass of the rock

a=20 m/s^2 is its acceleration

Therefore, the force applied on the rock is

F=ma=(20 kg)(20 m/s^2)=400 N


Veronika [31]3 years ago
4 0

Answer: The correct answer is 400 N.

Explanation:

The expression for the force in terms of mass and acceleration by using Newton's second law is as follows;

F=ma

Here, m is the mass of the object and a is the acceleration.

It is the given in the problem that the mass of the rock is 20 kg and the acceleration is 20 meter per second square.

Calculate the applied force.

Put m= 20 kg and a=  20 meter per second square in the above expression.

F= (20)(20)

F= 400 N

Therefore, the applied force is 400 N.

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Answer:

<em>a) 12614.4 m^3</em>

<em>b) 28.8 m</em>

Explanation:

The complete question is

Four astronauts are in a spherical space station. (a) If, as is typical, each of them breathes about 500 cm^3 of air with each breath, approximately what volume of air (in cubic meters) do these astronauts breathe in a year? (b) What would the diameter (in meters) of the space station have to be to contain all this air?

The average breathing rate is 12 breaths per minute

there are 60 minutes x 24 hours x 365 days in a year = 525600 minutes in a year

if an average human takes 12 breath per minute, then in a year an average human take 12 x 525600 = 6307200 breath

For the four astronauts, the amount of breath = 4 x 6307200 = 25228800 breath in total.

The volume of air per breath = 500 cm^3

1 cm^3 = 10^-6 m^3

500 cm^3 = x m^3

x = 500 x 10^-6 = 5 x 10^-4 m^3

Therefore in a year, the volume of these astronauts breath in a year = 5 x 10^-4 x 25228800 = <em>12614.4 m^3</em>

b) If the space station is spherical, the volume will be given as = \frac{4}{3} \pi r^3

where r is the radius of the space station

This volume of the space station must be able to contain all the volume of breath produced by the astronauts which is = 12614.4 m^3

Equating, we have

12614.4 = \frac{4}{3} \pi r^3

12614.4 = \frac{4}{3}*3.142*r^3

12614.4 = 4.1893r^{3}

r^{3} = 12614.4/4.1893 = 3011.1

r = \sqrt[3]{3011.1} =<em> 14.4 m</em>

<em>diameter of the space station = 14.4 m x 2 =  28.8 m</em>

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