Ask question

Ask question

All categories

2 years ago

8

MRU(movimiento rectilineo uniforme) un movil viaja en linea recta con una velocidad media de 12metros /segundos durante 9segundo

s y luego con una velocidad media de 4.8metros/segundos durante 7 segundos siendo ambas velocidades al mismo sentido. a) cual es el desplazamiento total del viaje de 16 segundos? b) cual es la velocidad media del viaje completo?

1 answer:

liubo4ka [24]2 years ago

8 0

Answer:

a) 141.6m

b) 8.4m/s

Explanation:

a) to find the total displacement you use the following formula for each trajectory. Next you sum the results:

$x_1=v_1t_1=(12m/s)(9s)=108m\\\\x_2=v_2t_2=(4.8m/s)(7s)=33.6m\\\\x_T=x_1+x_2=108m+33.6m=141.6m$

hence, the total distance is 141.6m

b) the mean velocity of the total trajectory is given by:

$v_m=\frac{v_1+v_2}{2}=\frac{12m/s+4.8m/s}{2}=8.4\frac{m}{s}$

hence, the mean velocity is 8.4 m/s

You might be interested in

How much energy is needed to heat and melt 3.0 kg of copper initially at 83°C?

Ne4ueva [31]

As we know that in order to melt the copper we need to take the temperature of copper to its melting point

So here heat required to raise the temperature of copper is given as

$Q = ms\Delta T$

We know that

melting temperature of copper = 1085 degree C

Specific heat capacity of copper = 385 J/kg C

now we have

$Q = 3(385)(1085 - 83)$

$Q = 1157310 J$

$Q = 1157.3 kJ$

now in order to melt the copper we know the heat required is

$Q = mL$

here we know that

L = 205 kJ/kg

now from above formula

$Q = 3(205) kJ$

$Q = 615 kJ$

now total heat required will be

$Q = 1157.3 kJ + 615 kJ$

$Q = 1772.3 kJ$

As we know that

$1 Cal = 4.18 kJ$

now we have

$Q = \frac{1772.3}{4.18} = 430 KCal$

6 0

2 years ago

What is the net work doneon the object over the distance shown?

GuDViN [60]

$A)F_0d$

Explanation

If you graph the force on an object as a function of the position of that object, then the area under the curve will equal the work done on that object, so we need to find the area under the function to find the work

Step 1

find the area under the function.

so

Area:

$\text{Area}=rec\tan gle_{green}+triangle_{gren}-triangle_{red}$ $\begin{gathered} \text{the area of a rectangle is given by} \\ A_{rec}=lenght\cdot widht \\ \text{and} \\ \text{the area of a triangle is given by:} \\ A_{tr}=\frac{base\cdot height}{2} \end{gathered}$

so

$\begin{gathered} \text{Area}=rec\tan gle_{green}+triangle_{gren}-triangle_{red} \\ \text{replace} \\ \text{Area}=(F_0\cdot d)+\frac{(F_0\cdot d)}{2}-\frac{(F_0\cdot d)}{2} \\ \text{Area}=(F_0\cdot d) \\ Area=F_0d \end{gathered}$

therefore, the answer is

$A)F_0d$

I hope this helps you

4 0

4 months ago

PLS HELP THIS IS WORTH 180 PTS!!(PLUS I WILL MARK BRAINIEST IF SOMEONE ANSWERS CORRECTY FIRST)

vazorg [7]

$\qquad\qquad\huge\underline{{\sf Answer}}$

The correct choice is ~ A

Bikes don't require gasoline for their functioning, so it causes less air pollution.

7 0

1 year ago

Read 2 more answers

If ice has a density of.92g/cm, what is the volume of 1.8 kilograms of ice?

steposvetlana [31]

Given:
Density = .92 g / cm³
Volume = 1.8 kg
= (1.8 * 1000) grams
= 1800 grams
Now,
$Density (d) = \frac{Mass (m)}{volume(v)}$

$volume (v)= \frac{mass(m)}{density(d)}$

$volume (v)= \frac{1800}{.92}$

$volume (v)= 1956.521739$

$volume (v)= 1956.5~ cm^{3}$

So, the volume of 1.8 kg of ice is 1956.5 cm³

5 0

2 years ago

Name three variables that affect a life system

sweet-ann [11.9K]

Three things that effect a life system would be
- sunlight
-water
-energy/food

Hope this helps

7 0

2 years ago

Read 2 more answers