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Fynjy0 [20]
3 years ago
8

MRU(movimiento rectilineo uniforme) un movil viaja en linea recta con una velocidad media de 12metros /segundos durante 9segundo

s y luego con una velocidad media de 4.8metros/segundos durante 7 segundos siendo ambas velocidades al mismo sentido. a) cual es el desplazamiento total del viaje de 16 segundos? b) cual es la velocidad media del viaje completo?
Physics
1 answer:
liubo4ka [24]3 years ago
8 0

Answer:

a) 141.6m

b) 8.4m/s

Explanation:

a) to find the total displacement you use the following formula for each trajectory. Next you sum the results:

x_1=v_1t_1=(12m/s)(9s)=108m\\\\x_2=v_2t_2=(4.8m/s)(7s)=33.6m\\\\x_T=x_1+x_2=108m+33.6m=141.6m

hence, the total distance is 141.6m

b) the mean velocity of the total trajectory is given by:

v_m=\frac{v_1+v_2}{2}=\frac{12m/s+4.8m/s}{2}=8.4\frac{m}{s}

hence, the mean velocity is 8.4 m/s

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To what temperature must you raise a silver wire (c = 0.0038), originally at 20.0°C, to double its resistance, neglecting any ch
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Answer:

T=283^{\circ}C

Explanation:

Given a material with temperature coefficient of resistance <em>c</em>, the equation that relates the resistance R_0 at temperature T_0 and the resistance R at temperature T is

\frac{R-R_0}{R_0}=c(T-T_0)

We want to double our resistance, so R=2R_0, thus having:

\frac{2R_0-R_0}{R_0}=\frac{R_0}{R_0}=1=c(T-T_0)

For this T must be:

1=cT-cT_0

T=\frac{1+cT_0}{c}

which for our values means (with T=20^{\circ}C=293^{\circ}K, remember to write temperature in S.I., and that for silver c=0.0038^{\circ}K^{-1}):

T=\frac{1+(0.0038^{\circ}K^{-1})(293^{\circ}K)}{(0.0038^{\circ}K^{-1})}=556^{\circ}K=283^{\circ}C

3 0
3 years ago
Light waves are electromagnetic waves that travel at 3.00 Light waves are electromagnetic waves that travel 108 m/s. The eye is
svlad2 [7]

(a) 5.45 \cdot 10^{14} Hz

The relationship between frequency and wavelength of an electromagnetic wave is given by

c=f \lambda

where

c=3.00 \cdot 10^8 m/s is the speed of light

f is the frequency

\lambda is the wavelength

In this problem, we are considering light with wavelength of

\lambda=5.50 \cdot 10^{-7} m

Substituting into the equation and re-arranging it, we can find the corresponding frequency:

f=\frac{c}{\lambda}=\frac{3.00 \cdot 10^8 m/s}{5.50 \cdot 10^{-7} m}=5.45 \cdot 10^{14} Hz

(b) 1.83\cdot 10^{-15} s

The period of a wave is equal to the reciprocal of the frequency:

T=\frac{1}{f}

And using f=5.45 \cdot 10^{14} Hz as we found in the previous part, we can find the period of this wave:

T=\frac{1}{5.45 \cdot 10^{14} Hz}=1.83\cdot 10^{-15} s

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3 years ago
An astronaut is rotated in a horizontal centrifuge at a radius of 5.0 m. (a) What is the astronaut’s speed if the centripetal ac
sergeinik [125]

Explanation:

Given that,

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a=\dfrac{v^2}{r}

v=\sqrt{ar}

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olga_2 [115]

At Divergent boundary, Crust is created.

At Convergent boundary, Crust is destroyed.

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<h3>What occurs at Divergent, Convergent and Transform boundary?</h3>

A divergent boundary occurs when two tectonic plates move away from each other. At this boundary, new oceanic crust is created.

Convergent boundaries are those boundaries where two plates are pushing into each other. These boundaries are pushing one of the plates under the other and back into the mantle to melt.

Transform boundaries are places where plates slide sideways past each other. At this boundary, Crust is neither created nor destroyed.

Learn more about boundary here: brainly.com/question/14298823

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