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Sphinxa [80]
3 years ago
11

Two electrons are separated by 1.70 nm. What is the magnitude of the electric force each electron exerts on the other?

Physics
1 answer:
lidiya [134]3 years ago
8 0

Answer:

F=7.96*10^{-11}N

Explanation:

According to Coulomb's law, the magnitude of the electric force between two equals charges (q) is given by:

F=\frac{kq^2}{d^2}

Here k is the coulomb constant and d is the distance between the charges. For two electrons we have:

F=\frac{ke^2}{d^2}\\F=\frac{8.99*10^{9}\frac{N\cdot m^2}{C^2}(-1.6*10^{-19}C)^2}{(1.7*10^{-9}m)^2}\\F=7.96*10^{-11}N

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