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3 years ago

How does the attraction between particles affect the ability of a solvent to dissolve in a substance

Chemistry

2 answers:

marysya [2.9K]3 years ago

8 0

Answer:

The correct answer is due to solubility.

Explanation:

The solubility of a substance called solvent in another called solute is determined by the balance of intermolecular forces between the solvent and solute. This is expressed by the variation in entropy that accompanies solvation. Factors that can vary such as temperature and pressure influence this equilibrium, thus changing the solubility of the substances.

Have a nice day!

Anni [7]3 years ago

6 0

Explanation:

The attraction between solute particles affect its ability to dissolve in the solution because more is the attraction between particles less will be the chances that solute particles will combine to the solvent particles.

As a result, there will be decrease in solubility with increase in force of attraction between solute particles.

Whereas when there is less force of attraction between solute particles then more easily solute particles will combine with the solvent particles.

Hence, with decrease in force of attraction between solute particles, the rate of dissolution will increase.

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2 years ago

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Cience, Life Science

Rudiy27

Answer:

I think the answer is All of these answers are correct.

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3 years ago

The PH of a 0.1 M MCl (M is an unknown cation) was found to be 4.7. Write the net ionic equation for the hydrolysis of M and its

Serggg [28]

Answer:

6.25 X10^{-9} = Ka

$Kb= \frac{10^{-14}}{6.25 X10^{-9}}= 1.6X10^{-6}$

Explanation:

The ionic equation for the hydrolysis of the cation of the given salt will be:

$M^{+} + H_{2}O ---> MOH + H^{+}$

The expression for Ka will be:

Ka = $\frac{[H^{+}][MOH]}{[M^{+}]}$

As given that the concentration of the salt is 0.1 M and pH of solution = 4.7, we can determine the concentration of Hydrogen ions from the pH

pH = -log [H⁺]

[H⁺] = antilog(-pH) = antilog (-4.7) = 2 X 10⁻⁵ M = [MOH]

Let us calculate Ka from this,

Ka = ${2.5X10^{-5}X2.5X10^{-5}}{0.1} = 6.25 X10^{-9}$

The relation between Ka an Kb is

KaXKb =10⁻¹⁴

$Kb= \frac{10^{-14}}{6.25 X10^{-9}}= 1.6X10^{-6}$

6 0

3 years ago

2a. What is the difference between weight and mass?

Dafna1 [17]

Mass is the amount of matter in the body.

Weight is the measure of force.

3 0

1 year ago

If 0.025 gram of Pb(NO3)2 is dissolved in 100. grams of H2O, what is the concentration of the resulting solution, in parts per m

anastassius [24]

Answer:

249.94ppm

Explanation:

Given parameters:

Mass of Pb(NO₃)₂ = 0.025g

Mass of water = 100g

Unknown:

Concentration of solution in ppm = ?

Solution:

Concentration in parts per million gives the amount of solute found in a million units of the solution. They are desirable for expressing very small amount of solutes in a large solution. For example, the level of arsenic in the soil.

Concentration in ppm = $\frac{amount of solute}{amount of solution} x 10^{6}$

A solution is made up of solute and solvent. The solvent here is water.

mass of solution = mass of solute + mass of solvent = 0.025 + 100 = 100.025g

Concentration in ppm = $\frac{0.025}{100.025} x 10^{6}$ = 249.94ppm

4 0

3 years ago