<u>Answer:</u>
The mass of the atom depends on the sub atomic particles present in the nucleus of an atom.
That is, the protons and the neutrons.
Electrons are present around the nucleus and the mass is negligible since its mass is very very less.
<em>mass of a proton = 
</em>
<em>mass of a neutron = 
</em>
<em>mass of an electron = 
</em>
Mass number represents the mass of one particular isotope and it is a whole number for example, 
Mass number is 13 and atomic number is 6 for the carbon isotope C-13.
Atomic mass is different from mass number and it is a fraction since it is the average atomic mass of all the isotopes of an atom.
Atomic mass of C is 12.011 amu which we see in the periodic table is the average atomic mass of isotopes C-12, C-13 and C-14.
To solve this question, we will use Graham's law which states that:
(R1 / R2) ^ 2 = M2 / M1 where
R1 and R2 are the rates of effusion and M1 and M2 are the molar masses of the two gases.
From the periodic table, we can calculate the molar mass of O2 as follows:
molar mass of O2 = 2*16 = 32 grams
Therefore we have:
R1 / R2 = Ry / RO2 = 1/2
M1 is My we want to get
M2 is molar mass of O2 = 32 grams
Substitute in the above equation to get the molar mass of y as follows:
(1/2) ^2 = (32/My)
1/4 = 32/My
My = 32*4 = 128
Therefore, molar mass of gas y = 128 grams
Answer:
Properties of Alkaline Earth Metals
shiny.
silvery-white.
somewhat reactive metals at standard temperature and pressure.
readily lose their two outermost electrons to form cations with a 2+ charge.
low densities.
low melting points.
low boiling points.
Explanation:
Answer:
1 : 1.5
Explanation:
First Sample;
Ratio of sulfur and Oxygen
Mass of sulfur : Mass of oxygen
Mass of oxygen = Mass of sample - Mass of sulfur = 70 - 35 = 35g
35g : 35g
1 : 1
Second Sample;
Ratio of sulfur and Oxygen
Mass of sulfur : Mass of oxygen
Mass of oxygen = Mass of sample - Mass of sulfur = 70 - 28 = 42g
28g : 42g
1 : 1.5
Further reducing it to make oxygen 1;
0.6667 : 1
ratio in whole numbers of the masses of sulfur that combine with 1.00 g of oxygen between the two compounds;
0.6667 : 1
1 : 1.5
