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scoray [572]
3 years ago
7

If a girl hits a ball with a bat, then the ball _____. a) exerts no force on the bat b)exerts a smaller force on the bat than th

e bat exerts on the ball c) exerts a force on the bat equal to the force that the bat exerts on the ball
Physics
2 answers:
kolbaska11 [484]3 years ago
7 0
Newton's 3rd law: The ball exerts a force on the bat that is equal and opposite to the force exerted by the bat on the ball.
11Alexandr11 [23.1K]3 years ago
4 0

Answer:

c) exerts a force on the bat equal to the force that the bat exerts on the ball

Explanation:

As per Newton's III law we know that when some force is applied on a system then equal and opposite reaction force is exerted by that system on us.

This equal and opposite force is known as reaction force due to applied force which is known as action force.

So As per Newton's III law we can say that every action has equal and opposite reaction force.

So here we can say that when girl hit the ball with the bat then some force is exerted by the bat on the ball so the reaction force due to ball on bat will be there which is of same magnitude but that would be in opposite direction

so here correct answer will be

c) exerts a force on the bat equal to the force that the bat exerts on the ball

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If a wave is traveling at 60cm/second and has a wavelength of 15 cm what is the frequency?
REY [17]
The frequency of the wave is 4 Hz
4 0
2 years ago
What velocity does a 2kg mass have when its kinetic energy is 16 J
alexandr402 [8]
We can use the equation for kinetic energy, K=1/2mv².
Your given variables are already in the correct units, so we can just plug in the variables and solve for v. 

K = 1/2mv²
16 = 1/2(2)v²
16 = (1)v²
√16 = v
v = 4 m/s

Therefore, the velocity of a 2 kg mass with 16 J of kinetic energy is 4 m/s.
Hope this is helpful!
7 0
2 years ago
A Hall probe, consisting of a rectangular slab of current-carrying material, is calibrated by placing it in a known magnetic fie
Citrus2011 [14]

Answer:

(a) 0.345 T

(b) 0.389 T

Solution:

As per the question:

Hall emf, V_{Hall} = 20\ mV = 0.02\ V

Magnetic Field, B = 0.10 T

Hall emf, V'_{Hall} = 69\ mV = 0.069\ V

Now,

Drift velocity, v_{d} = \frac{V_{Hall}}{B}

v_{d} = \frac{0.02}{0.10} = 0.2\ m/s

Now, the expression for the electric field is given by:

E_{Hall} = Bv_{d}sin\theta                            (1)

And

E_{Hall} = V_{Hall}d

Thus eqn (1) becomes

V_{Hall}d = dBv_{d}sin\theta

where

d = distance

B = \frac{V_{Hall}}{v_{d}sin\theta}                      (2)

(a) When \theta = 90^{\circ}

B = \frac{0.069}{0.2\times sin90} = 0.345\ T

(b) When \theta = 60^{\circ}

B = \frac{0.069}{0.2\times sin60} = 0.398\ T

5 0
2 years ago
75 POINTS AND BRAINLY
kramer

Answer:

B=work=power/time

Explanation:

8 0
2 years ago
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Different between these term<br> A)scalar and vector and give these example<br> B)speed and velocity
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