Answer: V = 504m/a
F = 4N
Explanation: please find the attached file for the solution
The speed of light in vacuum is exactly
299,792,458 meters per second.
That's so exact that it's the official scientific definition of a "meter".
The number doesn't t change even if the flashlight or other light source is moving.
Answer:
A) F=-20.16×10⁹N
B) if the distance doubles, force is 4 times smaller.
Explanation:
q1=-28C
q2=5mC=0.005C
d=25cm=0.25m
Electrostatic force between charges: F=k×q1×q2/d², where k is a coefficient that has the value k=9 × 10⁹ N⋅m²⋅C^(-2) for air.
Thus:
F=9×10⁹×(-28)×0.005/0.25²
F=-20.16×10⁹N
The minus sign indicates attraction.
If distance doubles, d1=2×d, then we have 4d² at the denominator and the force is 4 times smaller.
The correct answer is Mechanics
