Question

a load of 800 newton is lifted by an effort of 200 Newton. if the load is placed at a distance of 10 cm from the fulcrum. what will be the effort distance ?​

Answer 1

Answer:

40 cm

Explanation:

We are given that

Load=800 N

Effort=200 N

Load  distance=10 cm

We have to find the effort distance.

We know that

$load\times load\;distance=Effort\times effort\;distance$

Using the formula

$800\times 10=200\times effort\;distance$

Effort distance=$\frac{800\times 10}{200}$

Effort distance=$\frac{8000}{200}$

Effort distance=40 cm

Hence,  the effort distance will be 40 cm.