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jek_recluse [69]
3 years ago
10

two thermometers, calibrated in celsius and fahrenheit respectively, are put into a liquid. the reading on the fahrenheit scale

is four times the reading on the celsius scale. the temperature of the liquid is:

Physics
1 answer:
Viefleur [7K]3 years ago
6 0
Two thermometers, calibrated in celsius and fahrenheit respectively, are put into a liquid. the reading on the fahrenheit scale is four times the reading on the celsius scale. the temperature of the liquid is:

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Gekata [30.6K]

B, John Dalton. He thought that the atom was the smallest particle in the universe


8 0
3 years ago
A child of mass 46.2 kg sits on the edge of a merry-go-round with radius 1.9 m and moment of inertia 130.09 kg m2 . The merrygo-
Vedmedyk [2.9K]

Answer:

The angular velocity is w_f = 4.503 \  rad/s

Explanation:

From the question we are told that

   The mass of the child is  m_c  =  46.2 \ kg

    The radius of the merry go round is  r =  1.9 \ m

     The moment of inertia of the merry go round is I_m =  130.09 \  kg \cdot  m^2

      The angular velocity of the merry-go round is  w =  2.4 \ rad/s

       The position of the child from the center of the merry-go-round is  x = 0.779 \ m

According to the law of angular momentum conservation

    The initial angular momentum  =  final  angular momentum

So  

       L_i  =  L_f

=>     I_i w_i  =  I_fw_f

Now   I_i is the initial moment of inertia of the system which is mathematically represented as

          I_i  = I_m + I_{b_1}

Where  I_{b_i} is the initial moment of inertia of the boy which is mathematically evaluated as

      I_{b_i} =  m_c * r

substituting values

      I_{b_i} =  46.2 *  1.9^2

      I_{b_i} =  166.8 \ kg \cdot m^2

Thus

   I_i  =130.09 + 166.8        

   I_i  = 296.9 \ kg \cdot m^2      

Thus  

     I_i * w_i  =L_i=  296.9 * 2.4

       L_i  = 712.5 \ kg \cdot m^2/s

Now  

     I_f =  I_m  + I_{b_f }

Where  I_{b_f} is the final  moment of inertia of the boy which is mathematically evaluated as

         I_{b_f} =  m_c * x

substituting values

         I_{b_f} =  46.2 * 0.779^2

         I_{b_f} =  28.03  kg \cdot m^2

Thus

      I_f =  130.09 + 28.03

      I_f =  158.12 \ kg \ m^2

Thus

     L_f  =  158.12 * w_f

Hence

      712.5  =  158.12 * w_f

       w_f = 4.503 \  rad/s

8 0
3 years ago
Mechanical waves travel faster through _______ than through _______.
Over [174]
They travels faster through liquids than solids do...
hope that helps

4 0
3 years ago
Read 2 more answers
An engineer in a locomotive sees a car stuck on the track at a railroad crossing in front of the train. When the engineer first
GarryVolchara [31]

Answer:

The right answer is "1.369 m/s²".

Explanation:

The given values are:

Distance (s)

= 260 m

Initial speed (u)

= 26 m/s

Reaction time (t')

= 0.51 s

During reaction time, the distance travelled by locomotive will be:

⇒  s'=ut'

        =26\times 0.51

        =13.26 \ m

Remained distance between locomotive and car:

⇒  x=s-s'

         =260-13.26

         =246.74 \ m

Now,

The final velocity to avoid collection is, V = 0 m/s

From third equation of motion:

⇒  V^2=u^2+2ax

On putting the estimated values, we get

⇒  0=(26)^2+2\times a\times 246.74

⇒  0=676+493.48a

⇒  493.48a=-676

⇒            a=-\frac{676}{493.48}

⇒            a=1.369 \ m/s^2

3 0
3 years ago
A stone is dropped down a well and hits the water 2.50 s later. What is the depth from the edge of the well to the water? 61.3,
Gennadij [26K]

Answer;

30.6 m

Explanation;

All objects accelerate at the constant rate in the Earth's gravitational field. The gravitational acceleration, g = 9.8 m/s².

Distance traveled by an object falling down under a constant acceleration will be given the formula;

s = ut² + 1/2(gt²); but u the initial velocity is o

thus;

S =1/2(gt²)

  = 0.5 × 9.81 × 2.5 ²

  = 30.65

  ≈ 30.6 m

5 0
3 years ago
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