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AVprozaik [17]
3 years ago
8

How is plastic deformation related to high temperature and pressure?

Physics
1 answer:
Yuliya22 [10]3 years ago
7 0

Answer:

Plastic deformation of the cutting edge occurs when the tool material softens at high temperature and begins to flow under the pressure of the cutting forces. ... With cemented carbides, the higher the percentage of the binding phase (usually cobalt), the greater will be the deformation.

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The slowest moving animal is a crab found in the Red Sea. It travels with an average speed of 5.7 Km/year How long will it take
Anastasy [175]

Time = distance / speed

Time = (100 km) / (5.7 km/yr)

<em>Time = 17.5 years</em>

If this is true, then it's not likely that any member of the species has ever traveled 100 km in its lifetime.  Weird !

6 0
3 years ago
Two skaters collide and grab on to each other on frictionless ice. One of them, of mass 66.0 kg , is moving to the right at 2.00
ivann1987 [24]

Answer:

The velocity of skaters after collision is 0.55 m/s and they are moving to the left

Explanation:

Consider m₁ and m₂ are the masses of two skaters and their initial velocity be v₁ and v₂ respectively.

Consider the velocity along right direction as positive while negative for left direction.

According to the problem,

Mass of first skater, m₁ = 66.0 kg

Mass of second skater, m₂ = 75.0 kg

Velocity of first skater, v₁ = + 2.00 m/s

Velocity of second skater, v₂ = -2.80 m/s

Since, the two skaters grab each other after collision. Hence, they are moving with same final velocity v.

Applying conservation of linear momentum,

Momentum before collision = Momentum after collision

m₁v₁ + m₂v₂ = (m₁+m₂)v

Substitute the suitable values in the above equation.

66 x 2 - 75 x 2.8 = (66 + 75 )v

v= \frac{-78}{141}

v = -0.55 m/s

The negative sign denotes that both the skaters are moving in the left direction.

6 0
4 years ago
The transfer of the heat by the direct contact of particles of matter is
Anna007 [38]
C.c<span>onduction,  is the transfers of heat between substances that are in direct contact.</span>
3 0
3 years ago
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6 0
3 years ago
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A student buys a plastic dart gun and tries to find the maximum horizontal range. The student shoots the gun straight up and it
ryzh [129]

Answer:

The value is R_{max}  = 33.54 \  m

Explanation:

From the question we are told that

    The total time of flight is  t =  3.7 \  s

Generally from kinematic equation

        v  =  u -   g * \frac{t}{2}

So v is the velocity at maximum height and the value is  v = 0 m/s

So

       0   =  u -   9.8 * \frac{ 3.7}{2}

=>   u  =  18.13  \  m/s

Here u  is the initial velocity of the dart as it leaves that gun  

Gnerally the horizontal range of the dart is mathematically represented as

         R  =  \frac{u ^2 sin 2\theta }{g}

For maximum horizontal range the value of  \theta  =  45^o        

So

         R_{max}  =  \frac{ 18.13 ^2 sin 2(45) }{9.8}

=>     R_{max}  = 33.54 \  m

6 0
3 years ago
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