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Andre45 [30]
3 years ago
6

A baseball (m=140g) traveling 32m/s moves a fielders

Physics
1 answer:
posledela3 years ago
7 0

Answer:

Average force, F = 286.72 N

Explanation:

Given that,

Mass of the baseball, m = 140 g = 0.14 kg

Speed of the ball, v = 32 m/s

Distance, h = 25 cm = 0.25 m

We need to find the average  force exerted by the ball on the glove. It is solved using the conservation of energy as :

\dfrac{1}{2}mv^2=mgh

F = mg

\dfrac{1}{2}mv^2=Fh

F=\dfrac{mv^2}{2h}

F=\dfrac{0.14\times (32)^2}{2\times 0.25}

F = 286.72 N

So, the average force exerted by the ball on the glove is 286.72 N. Hence, this is the required solution.

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Students asked to measure the temperature of a reaction beaker recorded the following temperatures. 103.7°C, 108.4°C, 105.8°C, 1
zavuch27 [327]

Answer:

The measurement which is the most precise is 104.6 °C.

Explanation:

The measurement which is most precise must be very close to the actual value of the temperature.

Thus, the unit which have less value of the |Δx| (error) must be most precise.

Thus,

Actual value = 105.1 °C

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Value = 108.4 °C

<u>|Δx| = 3.3 °C</u>

Value = 105.8 °C

<u>|Δx| = 0.7 °C</u>

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If electromagnetic radiation acted like particles in the double-slit experiment, what would be observed? (1 point)
ludmilkaskok [199]

If electromagnetic radiation acted like particles in the double-slit experiment, we would observe one bright band would appear in the center of the screen.

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In a double-slit experiment, single particles, such as photons, pass one at a time through a screen containing two slits.

The photons behave like wave and the constructive interfernce of the waves of these photons will generate a high amplitude wave seen as a bright band in the center of the screen.

Thus, if electromagnetic radiation acted like particles in the double-slit experiment, we would observe one bright band would appear in the center of the screen.

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6 0
2 years ago
You have a string with a mass of 0.0133 kg. You stretch the string with a force of 8.89 N, giving it a length of 1.97 m. Then, y
Kazeer [188]

Answer:

(i) The wavelength is 0.985 m

(ii) The frequency of the wave is 36.84 Hz

Explanation:

Given;

mass of the string, m = 0.0133 kg

tensional force on the string, T = 8.89 N

length of the string, L = 1.97 m

Velocity of the wave is:

V = \sqrt{\frac{F_T}{M/L} } \\\\V = \sqrt{\frac{8.89}{0.0133/1.97} } \ = 36.29 \ m/s

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Fourth harmonic of a string with two nodes, the wavelength is given as,

L = 2λ

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(ii) Frequency of the wave is:

v = fλ

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3 years ago
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