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leonid [27]
3 years ago
10

A 0.80 kg mass attached to an ideal spring oscillates horizontally with a period of 0.50 s and amplitude of 0.30 m. What is the

spring constant of the spring?
Physics
1 answer:
sasho [114]3 years ago
8 0

Answer:

126.33 N/m

Explanation:

Angular frquency is given by

f=\frac {2\pi}{t}

Wheret is period of wave and f is angular frequency.

Given period of 0.5 s then

w=\frac {2\pi}{0.5}=4\pi rad/s\approx 12.57 rad/s

Angular frequency is also given by

w=\sqrt{\frac {k}{m}}

Making k the subject then k=mw^{2}

Where k is spring constant, m is mass

Substituting m with 0.8 then

k=0.8\times (4\pi)^{2}

K=126.330936333944 N/m

Rounded off as 126.33 N/m

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F = G m1*m2 / r^2 => [G] = [F]*[r]^2 /([m1]*[m2]) = N * m^2 / kg^2

That is one answer.

Also, you can use the fact that N = kg*m/s^2

[G] = kg * m / s^2 * m^2 / kg^2 = m^3 /(s^2 * kg)
5 0
3 years ago
Why does the cyclist have less kinetic energy at position A than at position B?
Semmy [17]
Suppose that the cyclist begins his journey from the rest from the top of a wedge with a slope of a degree above the horizontal.
 At point A (where it starts its journey), the energy is:
 Ea = m * g * h
 In other words, energy is only potential.
 At point B (located at the bottom of the wedge), the energy is:
 Eb = (1/2) * (m) * (v ^ 2)
 In other words, the energy is only kinetic.
 For energy conservation we have:
 Ea = Eb
 That is, we have that all potential energy is transformed into kinetic energy.
 Which means that the cyclist has less kinetic energy at point A because that's where he has more potential energy.
 answer:
 the cyclist has less kinetic energy at point A because that's where he has more potential energy.
6 0
4 years ago
A bubble, located 0.200 m beneath the surface in a glass of beer, rises to the top. The air pressure at the top is 1.01 ???? 10
SIZIF [17.4K]

Answer:

the ratio of the bubble’s volume at the top to its volume at the bottom is 1.019

Explanation:

given information

h = 0.2 m

P_{0} = 1.01  x 10^{5} Pa

P_{1} V_{1} = P_{2} V_{2}

\frac{V_{2} }{V_{1}} = \frac{P_{1} }{P_{2}}

P_{1}  = P_{0}  + ρgh, ρ = 1000 kg/m^{3}

P_{1}  = 1.01 x 10^{5} Pa + (1000 x 9.8 x 0.2) = 1,0296 x 10^{5} Pa

P_{2}  = P_{0}  = 10^{5} Pa

thus,

\frac{V_{2} }{V_{1}} = 1,0296 x [tex]10^{5}/10^{5} = 1.019

8 0
3 years ago
How far will a runner travel if she had an average speed of 10 km/hour and runs for 2.1 hours?
Rasek [7]
10 Km.
S= Speed
D= distance 
T= time

S= d/t
but since you are solving for "d" the equation is d=st so you plug in 10 km/h for speed and 2.1 hours for time and just multiply them. The hours cancel out so you are left with 10km.
8 0
3 years ago
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What is the effect of pressure on the solubility of gases in liquids?
34kurt
The solubility of gases in liquids increases with the increase in pressure.
3 0
3 years ago
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