It's the Methyl Orange.
at about 4.4 pH, it changes from red to Yellow, to indicate an acid solution.
This pH indicator is normally used in titration of acids.
Hope this Helps :)
At constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 20.85L.
<h3>
What is
Avogadro's law?</h3>
Avogadro's law states that "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules."
It is expressed as;
V₁/n₁ = V₂/n₂
Given the data in the question;
- Initial amount of gas n₁ = 2moles
- Initial volume v₁ = 13.9L
- Final amount of gas n₁ = 3moles
V₁/n₁ = V₂/n₂
V₁n₂ = V₂n₁
V₂ = V₁n₂ / n₁
V₂ = (13.9L × 3moles) / 2moles
V₂ = 41.7molL / 2mol
V₂ = 20.85L
At constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 20.85L.
Learn more about Avogadro's law here: brainly.com/question/15613065
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Answer:
32.7 kilograms of aluminium oxide will be produced.
Explanation:

Mass of aluminum = 17.3 kg = 17300 g (1 kg = 1000 g )
Moles of aluminium = 
According to reaction, 2 moles of aluminum gives 1 mole of aluminum oxide,then 640.74 moles of aluminum will give:
of aluminum oxide
Mass of 320.37 moles of aluminum oxides:
320.37 mol × 102 g/mol = 32,677.74 g = 32.67774 kg ≈ 32.7 kg
32.7 kilograms of aluminium oxide will be produced.
Answer is: concentration of products increases (ammonia nad water).
Chemical reaction: heat + NH₄⁺ + OH⁻ ⇄ NH₃ + H₂<span>O.
</span>According to Le
Chatelier's Principle, the position of equilibrium moves to counteract the
change, because heat is increased, system consume that heat, so equilibrium is shifted to right, by decreasing concentration of reaactants and increasing concentration of product.
An electron in the 3s orbital. The order of electron orbital energy levels starting from lowest to highest is as follows: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p.