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Brums [2.3K]
2 years ago
7

How many liters of N2 gas are in 2.4 moles at STP?

Chemistry
1 answer:
Cerrena [4.2K]2 years ago
7 0

Answer:

any gas takes up 22.4L per mole so 2.4*22.4=53.76

Explanation:

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The equilibrium constant, Kp, for the following reaction is 0.497 at 500K.PCl5(g) PCl3(g) + Cl2(g)If an equilibrium mixture of t
Anestetic [448]

<u>Answer:</u> The equilibrium partial pressure of chlorine gas is 0.360 atm

<u>Explanation:</u>

For the given chemical equation:

PCl_5(g)\rightleftharpoons PCl_3(g)+Cl2(g)

The expression of K_p for above reaction follows:

K_p=\frac{p_{Cl_2}\times p_{PCl_3}}{p_{PCl_5}}

We are given:

K_p=0.497\\p_{PCl_3}=0.651atm\\p_{PCl_5}=0.471atm

Putting values in above equation, we get:

0.497=\frac{p_{Cl_2}\times 0.651}{0.471}\\\\p_{Cl_2}=0.360atm

Hence, the equilibrium partial pressure of chlorine gas is 0.360 atm

5 0
3 years ago
Where is the kinetic energy GREATEST?
Zarrin [17]
Kinetic Energy is greatest at the bottom of the highest point
4 0
2 years ago
22. A piece of wood board contains approximately 6.76 X 1023 molecules of wood, C2H4920, how
Licemer1 [7]

Answer:

<h2>1.23 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{6.76 \times  {10}^{23} }{6.02 \times  {10}^{23} }  =  \frac{6.76}{6.02}  \\  = 1.22923...

We have the final answer as

<h3>1.23 moles</h3>

Hope this helps you

5 0
3 years ago
What are the parts of a water molecule
astra-53 [7]

Answer:

2 hydrogen, 1 oxygen

Explanation:

H2 O

6 0
2 years ago
Calculate the mass of O2 produced if 3.450 g potassium chlorate is completely decomposed by heating in presence of a catalyst (m
sergiy2304 [10]

The reaction is:

2 KClO3(s) → 3 O2(g) + 2 KCl(s) <span>

<span>A catalyst simply lowers the activation energy so MnO2 is not part of the overall reaction.

By stoichiometry: 

<span>3.45 g KClO3 x 1 mol/ 122.55g KClO3 x 3 mol O2/ 2 mol KClO3 x 31.99g/ 1 mol O2 = 331.096/ 245.1 = 1.35 grams O2 produced 

Answer:
1.35 grams O2</span></span></span>
3 0
3 years ago
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