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olya-2409 [2.1K]
3 years ago
13

11x + 13 12x+6 Solve for x

Chemistry
2 answers:
mixas84 [53]3 years ago
4 0

Answer:

x = 7

Explanation:

Simplifying

11x + 13 = 12x + 6

Reorder the terms:

13 + 11x = 12x + 6

Reorder the terms:

13 + 11x = 6 + 12x

Solving

13 + 11x = 6 + 12x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-12x' to each side of the equation.

13 + 11x + -12x = 6 + 12x + -12x

Combine like terms: 11x + -12x = -1x

13 + -1x = 6 + 12x + -12x

Combine like terms: 12x + -12x = 0

13 + -1x = 6 + 0

13 + -1x = 6

Add '-13' to each side of the equation.

13 + -13 + -1x = 6 + -13

Combine like terms: 13 + -13 = 0

0 + -1x = 6 + -13

-1x = 6 + -13

Combine like terms: 6 + -13 = -7

-1x = -7

Divide each side by '-1'.

x = 7

Simplifying

x = 7

vesna_86 [32]3 years ago
4 0

Answer:Simple and best practice solution for 11x+13=12x+6 equation. ... + 6 Reorder the terms: 13 + 11x = 6 + 12x Solving 13 + 11x = 6 + 12x Solving for variable 'x'.

Explanation:

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Acetone can be easily converted to isopropyl alcohol by addition of hydrogen to the carbon–oxygen double bond. calculate the ent
Step2247 [10]

Answer:

-484kJ

Explanation:

Carry out bond energy calculation

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How are acids and ionic compounds similar?
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Acids are very similar, consider Formic Acid, HCOOH, the simplest of the Carboxylic Acids. It dissociates more than say Benzoic Acid, C6H5-COOH. But neither disassociate as fully as Nitric Acid HNO3.

So the relative disassociation of the H+ (proton), or H3O+, (Hydronium ion), from any of these in water vary for a number of reasons we need not consider now.

Here is a “Tricky One!” (And very nasty). Take HF liquid or gas. This is one of the strongest acids on Earth - AS A LIQUID compound OR GAS. It will dissociate essentially near completion! Eat the floor, and is very dangerous.

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3 years ago
Place each noble gas symbol in front of the appropriate partial electron configuration to create an accurate electron configurat
nydimaria [60]

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For the first series, the highest principal energy level has the number 4, so our noble gas should <em>at least </em>be one that is in the third period (numerically, the energy level is the same as the period number). That noble gas would be argon. The partial electron configuration given is not that of a noble gas (note: all noble gases have an electron configuration that contains <em>N</em>p⁶, where <em>N </em>= the highest principal energy level). So, the noble gas that appropriately precedes our first partial electron configuration is [Ar].

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Now that we hopefully have our fundamentals down, we can apply them to figure out the noble gases that precede the remaining partial electron configurations.

[Kr]5s²4d¹⁰5p⁵: This is the electron configuration of iodine.

[He]2s²2p⁵: This is the electron configuration of fluorine.

[Xe]6s²4f¹⁴5d¹⁰6p²: This is the electron configuration of lead.

[Ne]3s²2: This is the electron configuration of magnesium.

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