Mass of carbon = 0.1927 g
Mass of hydrogen = 0.02590 g
Mass of nitrogen = 0.1124 g
Mass of phosphorus = 0.1491 g
Mass of Oxygen = 0.8138 - ( 0.1927 + 0.02590 + 0.1124 + 0.1491 ) = 0.3337 g
Moles of C =
Moles of H = mol
Moles of O =
Moles of P =
Moles of N =
So, the empirical formula will be:
To make it a whole divide the moles of all elements by 0.00481.
Therefore, .
Molecular mass of ATP = 507 g/mol
Empirical formula = 164.063 g/mol
Molecular formula:
So, molecular formula is =
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Answer:
1. Based on the given question, 138.03 grams of NO₂ is reacting completely with 18.02 grams of H2O. However, in case when 359 grams of NO₂ is used then the grams of water consumed in the reaction will be,
= 359 × 18.02 / 138.03 = 46.87 grams of water.
2. As mentioned in the given case 138.03 grams of NO₂ generates 126.04 grams of HNO₃. Therefore, 359 grams of NO₂ will produce,
= 359 × 126.04 / 138.03
= 327.81 grams of HNO₃.
3. Based on the given question, 138.04 grams of NO₂ is generating 30.01 grams of NO. Therefore, 359 grams of NO₂ will generate,
= 359 × 30.01 / 138.04
= 78.04 grams of NO.
117 mL of 0.210 M K₂S solution
Explanation:
The question asks about the volume of 0.210 M K₂S (potassium sulfide) solution required to completely react with 175 mL of 0.140 M Co(NO₃)₂ (cobalt(II) nitrate).
We have the chemical reaction:
K₂S + Co(NO₃)₂ → CoS + 2 KNO₃
molar concentration = number of moles / volume (L)
number of moles = molar concentration × volume
number of moles of Co(NO₃)₂ = 0.140 × 175 = 24.5 mmoles
We see from the chemical reaction that 1 mmole of Co(NO₃)₂ is reacting with 1 mmole of K₂S, so 24.5 mmoles of Co(NO₃)₂ are reacting with 24.5 mmoles of K₂S.
volume = number of moles / molar concentration
volume of K₂S solution = 24.5 / 0.210 = 117 mL
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The set AgCl > AgBr > AgI are arranged in order of decreasing solubility in water. In order to get the solubility, <span>it is measured in grams per 100 g of solvent – g/100 g – or number of moles per 1 L of the solution.</span>