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Aloiza [94]
3 years ago
13

Use the drop-down menus to complete each sentence.

Chemistry
2 answers:
Murrr4er [49]3 years ago
7 0

Answer:

1. group 2.period 3. less 4. more

Explanation:

Ipatiy [6.2K]3 years ago
3 0

Explanation:

Elements that belong to same group contains same number of valence electrons. Hence, they tend to show similar chemical properties.

When we move across a period then number of electrons get added to the same shell. As a result, there will be no increase in size of elements.

Also, metals are the elements that belong to group 1, 2 and d-block elements are also known as metals. Metallic character of elements decreases when we move left to right in a periodic table.

As most reactive metals are placed on the left side of periodic table.

Since, size of elements increases on moving down the group. So, an element is able to easily lose its valence electrons because of less force of attraction between its nucleus and valence electrons.

As a result, there will be increase in reactivity of metals on moving down the group.

Thus, we can conclude that given sentences are as follows.

  • Elements in the same group have the same number of valence electrons.
  • Elements in the same period have the same number of electron shells.
  • Metallic elements become less reactive as you move left to right in a period.
  • Metallic elements become more reactive as you move top to bottom in a group.
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Answer:

ΔfG°(C₆H₆(g)) = 129.7kJ/mol

Explanation:

Bringing out the parameters mentioned in the question;

Vapor pressure = 94.4 mm of Hg

The vaporization reaction is given as;

C₆H₆(l) ⇄ C₆H₆(g)

Equilibrium in terms of activities is given by:

K = a(C₆H₆(g)) / a(C₆H₆(l))

Activity of pure substances is one:

a(C₆H₆(l)) = 1

Assuming ideal gas phase activity equals partial pressure divided by total pressure. At standard conditions

K = p(C₆H₆(g)) / p°

Where p° = 1atm = 760mmHg standard pressure

We now have;

K = 94mmHg / 760mmHg = 0.12421

Gibbs free energy is given as;

ΔG = - R·T·ln(K)

where R = gas constant = 8.314472J/molK

So ΔG° of vaporization of benzene is:

ΔvG° = - 8.314472 · 298.15 · ln(0.12421)

ΔvG° = 5171J/mol = 5.2kJ/mol  

Gibbs free energy change of reaction = Gibbs free energy of formation of products - Gibbs free energy of formation of reactants:

ΔvG° = ΔfG°(C₆H₆(g)) - ΔfG°(C₆H₆(l))

Hence:

ΔfG°(C₆H₆(g)) = ΔvG°+ ΔfG°(C₆H₆(l))

ΔfG°(C₆H₆(g)) = 5.2kJ/mol + 124.5kJ/mol

ΔfG°(C₆H₆(g)) = 129.7kJ/mol

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