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Shkiper50 [21]
3 years ago
11

A sample of water at 100°C is converted to steam after absorbing 820 kJ of heat. How grams of H2O are contained in the sample? A

ssume that the molar heat of vaporization of water is 41 kJ/mol.
Chemistry
1 answer:
Varvara68 [4.7K]3 years ago
7 0
Since water is already at 100<span>°C all the energy is used to evaporate it. 
Now we can calculate how many </span>mols of water are evaporated with 820kJ.
N= \frac{820}{41} =20 mol
We calculated that we got 20 mols of water evaporated. Now, all we have to do is find how many grams is a mol of water. Molar mass of water is <span>20.16 g/mol.
</span>The final answer is:
m=20*20.16=403.2g




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kherson [118]

Answer: Thus 0.724 mol of CaCN_2 are needed to obtain 18.6 g of NH_3

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} NH_3=\frac{18.6g}{17g/mol}=1.09moles

CaCN_2+3H_2O\rightarrow CaCO_3+2NH_3

According to stoichiometry :

2 moles of NH_3 are produced by = 1 mole of CaCN_2

Thus 1.09 moles of NH_3 will be produced by =\frac{1}{2}\times 1.09=0.545moles  of CaCN_2

But as yield of reaction is 75.6 %, the amount of CaCN_2 needed is =\frac{0.545}{75.6}\times 100=0.724

Thus 0.724 mol of CaCN_2 are needed to obtain 18.6 g of NH_3

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Número cuántico que designa el nivel de energía en el que se localiza un electrón:
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