Answer:
The controlled variable of an experiment is the one thing that stays the same in an experiment.
Explanation:
An example would be : if I have two pennies, both dunked in water, but than I change one to be dunked in vinegar, the one dunked in water still is the constant or the controlled variable.
Na3PO4 + 3 KOH = 3 NaOH + K3PO4
First you need to know the value of Kp for this reaction. The reaction is: SO2 (g) + 2 H2S (g)<=> 3S(s) + 2 H2O(g): Kp = PH2O^2 / PSO2(PH2O)^2 but since the problem is lacking in details.
Otherwise, let x = PSO2 = PH2S. Then:
Kp = (22/760 atm)^2 / x^3
x = cube root (0.289)/Kp = PSO2
But if the kp is given, let us assume it is 8.0*10^15The solution would be:convert the given pressure of water to atm, which is: 0.029
Kp=P(H2O)^2/P(SO2)P(H2S)^2
8.0*10^15 = (0.029)^2/x^3
(8.0*10^15).(x^3)=8.41*10^-4
take the cube root of both sides(2.0*10^5).x = 9.439130*10^-2x = P (SO2) = 4.6*10^-7
D = g / cm³
Density = mass / volume
D = 360 g / 7.5 cm³
D = 48 g/cm³
answer D
hope this helps!