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Andrew [12]
3 years ago
9

The majority of the mass of the atom is located in the _______. A) nucleus B) core electrons C) pions and quarks D) valence elec

trons
Chemistry
2 answers:
NeX [460]3 years ago
5 0

The majority of the mass of the atom is located in the nucleus. Remember that the nucleus contains both protons and neutrons and therefore, most of the mass of the atom.

Helen [10]3 years ago
3 0

Answer:

A

Explanation:

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How many square centimeters are in an area of 9.90 inch2 ?
USPshnik [31]

Answer:

63.8708 hope this helps :)

Explanation:

7 0
2 years ago
A beaker contains 500 ml of 2.40M KNO3 the beaker is left uncovered so that all of the water evaporates. What mass of KNO3 cryst
telo118 [61]

Answer:

242.4 g

Explanation:

RAM of KNO3=39+14+(16×3)=101

Mass=morality×RAM

101*2.4=242.4

6 0
2 years ago
Jupiters atmosphere is mostly made of ___
erastovalidia [21]
Jupiter's atmosphere is composed predominantly of hydrogen and helium, but if you have to select any one option then we can look at the percentage of existence of these elements that would be
<span>90 percent hydrogen.
remaining 10 percent is helium 
so choose Hydrogen.</span>
3 0
3 years ago
BRAINLIESTTT ASAP!!!! PLEASE HELP ME :)
Elan Coil [88]

Answer:

1s² 2s²2p³  

Explanation:

If the atom has seven electrons, it is Element 7 (nitrogen).

In the Periodic Table, you count the electrons in all the subshells up to

No. 7.

In the first Period, you have filled the 1s level (2 electrons).

In the second Period, you have filled the 2s subshell (2 electrons) and put three electrons in the 2p subshell.

Thus, the electron configuration is

1s² 2s²2p³

Note how the superscripts tell you the number of electrons in each subshell: <em>2 + 2 + 3 = 7</em>.

6 0
2 years ago
La masa de una olla es de 300g y contiene 90% de aluminio. Hallar el número de moles de aluminio de la olla. P.A.(Al= 27)
Neko [114]

Explanation:

The mass of a pot is 300g and contains 90% aluminum. Find the number of moles of aluminum in the pot. P.A. (Al = 27)

The mass of aluminum present in the pot is:

300 g * 90/100\\=270 g

Hence, in the given pot 270g Al is present.

Number of moles of Al=\frac{given mass ofAl}{its molar mass}

The gram atomic mass of Al -27 g/mol

Given the mass of Al is 270 g

Substitute these values in the above formula:

Number of moles of Al=\frac{given mass ofAl}{its molar mass}\\=\frac{270 g}{27 g} \\=10.0 mol

Answer is 10.0 mol of Al is present.

6 0
2 years ago
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