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Sonbull [250]
3 years ago
8

We have 1700 Tonnes of Amoniac every day. How many tonnes of 63% Nitrogen soda we can get?

Chemistry
1 answer:
V125BC [204]3 years ago
3 0
There are 3 equations involved in manufacturing Nitric Acid from Ammonia. 

First the ammonia is oxidized:
4NH3 + 5O2 = 4NO + 6H2O

Then for the absorption of the nitrogen oxides.
2NO + O2 = N2O4

Lastly, the N2O4 is further oxidized into Nitric acid.
3N2O4 + 2H2O = 4HNO3 + 2NO

Then run stoichiometry through these equations.
The first equation produces roughly 271,722,938 grams of NO
The second equation produces roughly 416,606,944 grams of N2O4
The last equation produces roughly 380,412,294 grams of HNO3 (nitric acid)

Convert the exact number back into tons, and your answer is: 419.332775 tons.

Rounded, I'm going to say that's 419.33 tons.
Hope this helps! :)

Also, it seems that commercially, Nitric Acid is commonly made by bubbling NO2 into water, rather than using ammonia.
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3 years ago
Give the number of significant figures in this number: 7.8 x 10¹²
denis-greek [22]
The number is written in scientific notation.


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8 0
3 years ago
What is the theoretical yield of Li3N in grams when 12.8 g of Li is heated with 34.9 g of N2?
Olenka [21]

Answer:- 21.4 grams of Li_3N are formed.

Solution:- The balanced equation is:

6Li+N_2\rightarrow 2Li_3N

From this equation, lithium and nitrogen reacts in 6:1 mol ratio. Limiting reactant gives the theoretical yield of the product. We will calculate the grams of the product for the given grams of both the reactants and see which one of them gives the limited amount of the product. This limited amount of the product will be the theoretical yield.

The molar mass of Li is 6.94 gram per mol and for N_2 It is 28.02 gram per mol. The molar mass of Li_3N is 34.83 gram per mol. The calculations for the grams of the product for given grams of both the reactants are shown below:

12.8gLi(\frac{1molLi}{6.94gLi})(\frac{2molLi_3N}{6molLi})(\frac{34.83gLi_3N}{1molLi_3N})

= 21.4gLi_3N

34.9gN_2(\frac{1molN_2}{28.02gN_2})(\frac{2molLi_3N}{1molN_2})(\frac{34.83gLi_3N}{1molLi_3N})

= 86.8gLi_3N

From above calculations, Li gives least amount of the product. So, 21.4 g of Li_3N are formed.

4 0
2 years ago
Need help fast please
fenix001 [56]

Explanation:

When the reaction takes place,2 grams of carbon dioxide will be made but vaporized into air.

5 0
3 years ago
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kipiarov [429]
B 
hopes this helps!!!!!!!!!
4 0
3 years ago
Read 2 more answers
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