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3 years ago

We have 1700 Tonnes of Amoniac every day. How many tonnes of 63% Nitrogen soda we can get?

1 answer:

3 0

There are 3 equations involved in manufacturing Nitric Acid from Ammonia.

First the ammonia is oxidized:
4NH3 + 5O2 = 4NO + 6H2O

Then for the absorption of the nitrogen oxides.
2NO + O2 = N2O4

Lastly, the N2O4 is further oxidized into Nitric acid.
3N2O4 + 2H2O = 4HNO3 + 2NO

Then run stoichiometry through these equations.
The first equation produces roughly 271,722,938 grams of NO
The second equation produces roughly 416,606,944 grams of N2O4
The last equation produces roughly 380,412,294 grams of HNO3 (nitric acid)

Convert the exact number back into tons, and your answer is: 419.332775 tons.

Rounded, I'm going to say that's 419.33 tons.
Hope this helps! :)

Also, it seems that commercially, Nitric Acid is commonly made by bubbling NO2 into water, rather than using ammonia.

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What does the number of valence electrons determine?

N76 [4]

Valence electrons are the electrons in the outermost shell of an element on the periodic table. Atoms want to be able to have a full outer shell and they can share or trade electrons in order to achieve this. Valence electrons are also super super important in chemical reactions. The number of valence electrons determines what group that specific atom or element is in on the periodic table. This affects the reactivity of the element.

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3 years ago

what would happen if we lost our planets core on earth blew up, would we all die or will we lose gravity or suficate, pls help.

sergeinik [125]

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2 years ago

How much heat is lost when 1277 g of H20 at 400 K is changed into ice at 263 K? Plz help I’ll give you brainliest 20 points

OLga [1]

The heat lost is $-7.32*10^-^5J$

The heat lost when the ice is cooled from 400k to 263K can be calculated using the formula of heat transfer.

<h3>Heat Transfer</h3>

This is the heat transferred from a body of higher temperature to a body of lower temperature.

$Q = mc(\delta)T$

Q = Heat Transfer
m = mass = 1277g
ΔT = change in temperature

$\delta T = (400 - 273) - (263 - 273) = \\
\delta T = T_2 - T_1\\
\delta T = -10 - 127\\
\delta T = -137^0C$

We converted the temperature from kelvin scale into Celsius scale and find the change in temperature.

Solving for heat transfer

$Q = mc\delta T\\
Q = 1277 * 4.186 * -137\\
Q = -732336.514J$

The heat loss is approximately $-7.32*10^-^5J$

Learn more on heat transfer here;

brainly.com/question/16055406

6 0

2 years ago

What particles gives the nucleus its positive charge

Flauer [41]

Answer:

Protons

Explanation:

your welcome!

6 0

3 years ago

G. whose vapour

german

Answer:

8.33 hours

Explanation:

In order to solve this problem, we must apply Graham's law of diffusion in gases. Graham's law states that the rate of diffusion of a gas is inversely proportional to the square root of its vapour density. For two gases we can write;

R1/R2=√d2/d1

Where;

R1= rate of diffusion of hydrogen

R2= rate diffusion of unknown gas

d1= vapour density of hydrogen

d2= vapour density of the unknown gas

Volume of hydrogen gas = 360cm^3

Time taken for hydrogen gas to diffuse= 1 hour =3600 secs

R1 = 360 cm^3/3600 secs = 0.1 cm^3 s-1

Vapour density of unknown gas = 25

Vapour density of hydrogen = 1

Substituting values,

0.1/R2 = √25/1

0.1/R2 = 5/1

5R2 = 0.1 × 1

R2 = 0.1/5

R2= 0.02 cm^3s-1

Volume of unknown gas = 600cm^3

Time taken for unknown gas to diffuse= volume of unknown gas/ rate of diffusion of unknown gas

Time taken for unknown gas to diffuse= 600/0.02

Time= 30,000 seconds or 8.33 hours

8 0

3 years ago