<u>Answer:</u> The initial pH of the HCl solution is 3
<u>Explanation:</u>
To calculate the concentration of acid, we use the equation given by neutralization reaction:
![n_1M_1V_1=n_2M_2V_2](https://tex.z-dn.net/?f=n_1M_1V_1%3Dn_2M_2V_2)
where,
are the n-factor, molarity and volume of acid which is HCl
are the n-factor, molarity and volume of base which is NaOH.
We are given:
![n_1=1\\M_1=?M\\V_1=100mL\\n_2=1\\M_2=0.10M\\V_2=1mL](https://tex.z-dn.net/?f=n_1%3D1%5C%5CM_1%3D%3FM%5C%5CV_1%3D100mL%5C%5Cn_2%3D1%5C%5CM_2%3D0.10M%5C%5CV_2%3D1mL)
Putting values in above equation, we get:
![1\times M_1\times 100=1\times 0.10\times 1\\\\M_1=\frac{1\times 0.10\times 1}{1\times 100}=10M](https://tex.z-dn.net/?f=1%5Ctimes%20M_1%5Ctimes%20100%3D1%5Ctimes%200.10%5Ctimes%201%5C%5C%5C%5CM_1%3D%5Cfrac%7B1%5Ctimes%200.10%5Ctimes%201%7D%7B1%5Ctimes%20100%7D%3D10M)
1 mole of HCl produces 1 mole of
ions and 1 mole of
ions
To calculate the pH of the solution, we use the equation:
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
We are given:
![[H^+]=0.001M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D0.001M)
Putting values in above equation, we get:
![pH=-\log (0.001)\\\\pH=3](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%280.001%29%5C%5C%5C%5CpH%3D3)
Hence, the initial pH of the HCl solution is 3
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February or march probably
Answer:
A mixture!
Explanation:
Mixtures are a substance made of combining two or more different kinds of matter :)
Hope this helped!