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SCORPION-xisa [38]
3 years ago
7

Two different compounds are formed by the elements nitrogen and oxygen. The first compound, compound P1, contains 64.17% by mass

nitrogen and 35.73% by mass oxygen. The second compound, compound P2, contains 47.23% by mass nitrogen and 52.79% by mass oxygen. What is the ratio of nitrogen to a fixed mass of oxygen for the two compounds?
Chemistry
1 answer:
xz_007 [3.2K]3 years ago
7 0

Answer:

Explanation:

To solve the problem, we must know the kind of compounds we are dealing with.

For the first compound, P1 and second compound P2:

                                N                       O                         N                     O

Mass percent       64.17                 35.73                  47.23               52.79

Atomic mass          14                      16                         14                    16

Number of

moles            64.17/14            35.73/16            47.23/14    52.79/16      

                            4.58                  2.23                     3.37                  3.30

Simplest

ratio                 4.58/2.23            2.23/2.23             3.37/3.30         3.3/3.3

                              2                           1                             1                        1

                             

P1 compound is N₂O

P2 compound is NO

These are the compounds,

   In N₂O = 28:16

          NO = 14:16

This is the ratio of nitrogen to a fixed mass of oxygen for the two compounds.

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What is the molecular formula of a compound with the empirical formula so and molecular weight 96.13?
garik1379 [7]
<h3>Answer:</h3>

                  Molecular Formula  =  S₂O₂  (Disulfur Dioxide)

<h3>Solution:</h3>

Molecular formula is calculated by using following formula,

                    Molecular Formula  =  n × Empirical Formula  ---- (1)

Also, n is given as,

                     n  =  Molecular Weight / Empirical Formula Weight

Molecular Weight  =  96.13 g.mol⁻¹

Empirical Formula Weight  =  32.06 (S) + 16.0 (O)  =  48.06 g.mol⁻¹

So,

                     n  =  96.13 g.mol⁻¹ ÷ 48.06 g.mol⁻¹

                     n  =  2.0002 ≈ 2

Putting Empirical Formula and value of "n" in equation 1,

                    Molecular Formula  = 2 × SO

                    Molecular Formula  =  S₂O₂  (Disulfur Dioxide)

4 0
4 years ago
(b) Which peak, the one at 365 nm or the one at 435 nm, results from the absorption of
GenaCL600 [577]

Answer:

365nm and Exothermic reaction

Explanation:

b) The Einstein Planck's equation states that

E = hf where E is the energy of a photon

                     h  is the Planck's constant

                     f  is the frequency

But Frequency f = c/λ  where c  is the speed of light

                                                  λ  is the wavelength

Therefore Energy E = hc/λ

From the above equation we see that the Energy of a photon is indirectly proportional to its wavelength

Hence as the wavelength increases from 365nm to 435nm, the energy of the photons decreases

Therefore, a photon will wavelength 365nm would have a higher energy than one will wavelength of 435nm.

c) From the diagram we observe the following:

At high temperatures,   HPR⁺ occurs at a higher concentration than at low temperatures.

At low temperatures, more of PR⁻ is formed than at high temperatures

The equation of the reaction is

HPR⁺ (aq) ⁺ ⇆ H⁺ + PR⁻(aq)      

Le Chartelier's principle states that when an external constraint such as a change in concentration, pressure or temperature is placed on a system in equilibrium, the system acts in such a way as to oppose the change.

Hence a decrease in temperature on the side of reactant, HPR would force the equilibrium to the side of the products, PR in other to accommodate the change

The forward reaction, which produces more of the product PR⁻ is exothermic because  the at low temperatures, the the forward reaction is favoured and equilibrium shifts to the right.

5 0
3 years ago
The density of ethanol, C 2H 5OH, is 0.789 g/mL. How many milliliters of ethanol are needed to produce 25.0 g of CO 2 according
gogolik [260]

Answer:

11.1mL

Explanation:

The reaction expression is given as:

          C₂H₅OH   + 3O₂ → 2CO₂ +  3H₂O

Given parameters:

density of ethanol  = 0.789g/mL

mass of CO₂ = 25g

Unknown:

Volume of ethanol = ?

Solution:

First find the number of moles of the CO₂ from the given mass;

 Number of moles  = \frac{mass}{molar mass}

 Molar mass of CO₂ = 12 + 2(16) = 44g/mol

Number of moles  = \frac{25}{44}    = 0.57mol

Then;

 Find the number of moles of ethanol used;

     3 moles of CO₂ is produced from 1 mole of ethanol;

    0.57mole of CO₂ will be produced from \frac{0.57}{3}  = 0.19mole of ethanol

Now;

Find the mass of the ethanol from the given mole;

     Mass of ethanol  = number of moles x molar mass

     Molar mass of ethanol  = 2(12) + 5(1) + 16 + 1 = 46g/mol

      Mass of ethanol  = 0.19 x 46 = 8.74g

Then;

  Density is the mass per unit volume of a substance;

       Density  = \frac{mass}{volume}

        Volume  = \frac{mass}{density}  

          Volume  = \frac{8.74}{0.789}   = 11.1mL

5 0
3 years ago
Compound W, C6H11Cl, undergoes base-promoted E2 elimination to form a single alkene Y. Under similar reaction conditions X, C6H1
alexgriva [62]

Answer:

; The structures of both compounds are shown in the attached image.

Explanation:

First, compound W has the molecular formula C6H11Cl, it is observed that it does not have double bonds. removal of E2 produces compound Y, which is an alkene, which is hydrogenated and produces a methylcyclopentane.

Compound W is an alkyl halide that undergoes an SN1 reaction with sodium iodide in the presence of acetone forming the corresponding iodine compound.

while compound X is a tertiary alkyl halide, it is sterically restricted to undergo SN2 reactions.

4 0
4 years ago
Carbon is found in all organic molecules.<br> a. True<br> b. False
labwork [276]
That is, by definition, true.
5 0
4 years ago
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